Math  /  Algebra

QuestionSolve for aa. a+1920a+19 \geq 20

Studdy Solution

STEP 1

What is this asking? We need to find the smallest possible value for aa that makes the given inequality true. Watch out! Don't forget to flip the inequality sign if you multiply or divide both sides by a negative number, but we won't need to do that here!

STEP 2

1. Isolate aa
2. Final Inequality

STEP 3

We want to get aa by itself, so let's **subtract** 1919 from both sides of the inequality.
Remember, whatever we do to one side, we *must* do to the other to keep things balanced! a+19192019a + 19 - 19 \geq 20 - 19 This simplifies to: a1a \geq 1 Why did we subtract 19?
Because we're trying to isolate aa, and adding 1919 and subtracting 1919 add to zero, which doesn't change the value of the left side, but gets us closer to our goal!

STEP 4

Our final inequality is a1a \geq 1.
This tells us that aa can be any number that is **greater than or equal to** 1\textbf{1}.

STEP 5

The solution to the inequality a+1920a + 19 \geq 20 is a1a \geq 1.

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