QuestionSolve for $b$ in the equation: $\frac{a b + 5}{4} = c$ .

Studdy Solution

STEP 1

Assumptions1. We are given the equation $\frac{a b+5}{4}=c$ . We need to solve for $b$
3. $a$ , $b$ , and $c$ are real numbers4. $a$ and $c$ are known values5. $a$ is not equal to0

STEP 2

First, we need to isolate the term containing $b$ on one side of the equation. We can do this by multiplying both sides of the equation by4.
$4 \cdot \frac{a b+5}{4} =4 \cdot c$

STEP 3

implify the equation.
$a b+5 =c$

STEP 4

Next, we need to isolate $b$ by subtracting from both sides of the equation.
$a b+ - =4c -$

STEP 5

implify the equation.
$a b =4c -5$

STEP 6

Finally, we can solve for $b$ by dividing both sides of the equation by $a$ .
$b = \frac{4c -5}{a}$ So, the solution for $b$ is $\frac{4c -5}{a}$ .

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QuestionSolve for $b$ in the equation: $\frac{a b + 5}{4} = c$ .

Studdy Solution

STEP 1

Assumptions1. We are given the equation $\frac{a b+5}{4}=c$ . We need to solve for $b$
3. $a$ , $b$ , and $c$ are real numbers4. $a$ and $c$ are known values5. $a$ is not equal to0

STEP 2

First, we need to isolate the term containing $b$ on one side of the equation. We can do this by multiplying both sides of the equation by4.
$4 \cdot \frac{a b+5}{4} =4 \cdot c$

STEP 3

implify the equation.
$a b+5 =c$

STEP 4

Next, we need to isolate $b$ by subtracting from both sides of the equation.
$a b+ - =4c -$

STEP 5

implify the equation.
$a b =4c -5$

STEP 6

Finally, we can solve for $b$ by dividing both sides of the equation by $a$ .
$b = \frac{4c -5}{a}$ So, the solution for $b$ is $\frac{4c -5}{a}$ .

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QuestionSolve for bbb in the equation: ab+54=c\frac{a b + 5}{4} = c4ab+5​=c.

Studdy Solution

STEP 1

Assumptions1. We are given the equation ab+54=c\frac{a b+5}{4}=c4ab+5​=c . We need to solve for bbb3. aaa, bbb, and ccc are real numbers4. aaa and ccc are known values5. aaa is not equal to0

STEP 2

First, we need to isolate the term containing bbb on one side of the equation. We can do this by multiplying both sides of the equation by4.4⋅ab+54=4⋅c4 \cdot \frac{a b+5}{4} =4 \cdot c4⋅4ab+5​=4⋅c

STEP 3

implify the equation.ab+5=ca b+5 =cab+5=c

STEP 4

Next, we need to isolate bbb by subtracting from both sides of the equation.ab+−=4c−a b+ - =4c -ab+−=4c−

STEP 5

implify the equation.ab=4c−5a b =4c -5ab=4c−5

STEP 6

Finally, we can solve for bbb by dividing both sides of the equation by aaa.b=4c−5ab = \frac{4c -5}{a}b=a4c−5​So, the solution for bbb is 4c−5a\frac{4c -5}{a}a4c−5​.

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QuestionSolve for $b$ in the equation: $\frac{a b + 5}{4} = c$ .

Assumptions1. We are given the equation $\frac{a b+5}{4}=c$ . We need to solve for $b$
3. $a$ , $b$ , and $c$ are real numbers4. $a$ and $c$ are known values5. $a$ is not equal to0

First, we need to isolate the term containing $b$ on one side of the equation. We can do this by multiplying both sides of the equation by4.
$4 \cdot \frac{a b+5}{4} =4 \cdot c$

implify the equation.
$a b+5 =c$

Next, we need to isolate $b$ by subtracting from both sides of the equation.
$a b+ - =4c -$

implify the equation.
$a b =4c -5$

Finally, we can solve for $b$ by dividing both sides of the equation by $a$ .
$b = \frac{4c -5}{a}$ So, the solution for $b$ is $\frac{4c -5}{a}$ .