Math / Algebra

QuestionSolve for $s$ . $\begin{array}{l} -10 r+12 s=-6 \\ s=[] \end{array}$

Studdy Solution

STEP 1

1. The equation $-10r + 12s = -6$ is a linear equation in terms of $s$ .
2. We need to isolate $s$ on one side of the equation.
3. The equation involves basic algebraic operations such as addition, subtraction, and division.

STEP 2

1. Rearrange the equation to isolate terms involving $s$ .
2. Solve for $s$ by performing algebraic operations.
3. Verify the solution by substituting back into the original equation if necessary.

STEP 3

Start with the given equation:
$-10r + 12s = -6$
Our goal is to isolate $s$ . First, move the term involving $r$ to the other side of the equation by adding $10r$ to both sides:
$12s = 10r - 6$

STEP 4

Now, solve for $s$ by dividing every term by 12:
$s = \frac{10r - 6}{12}$
Simplify the expression if possible:
$s = \frac{10r}{12} - \frac{6}{12}$
$s = \frac{5r}{6} - \frac{1}{2}$

STEP 5

Verification is optional in this context, as the solution is expressed in terms of $r$ .
The solution for $s$ is:
$s = \frac{5r}{6} - \frac{1}{2}$

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QuestionSolve for $s$ . $\begin{array}{l} -10 r+12 s=-6 \\ s=[] \end{array}$

Studdy Solution

STEP 1

1. The equation $-10r + 12s = -6$ is a linear equation in terms of $s$ .
2. We need to isolate $s$ on one side of the equation.
3. The equation involves basic algebraic operations such as addition, subtraction, and division.

STEP 2

1. Rearrange the equation to isolate terms involving $s$ .
2. Solve for $s$ by performing algebraic operations.
3. Verify the solution by substituting back into the original equation if necessary.

STEP 3

Start with the given equation:
$-10r + 12s = -6$
Our goal is to isolate $s$ . First, move the term involving $r$ to the other side of the equation by adding $10r$ to both sides:
$12s = 10r - 6$

STEP 4

Now, solve for $s$ by dividing every term by 12:
$s = \frac{10r - 6}{12}$
Simplify the expression if possible:
$s = \frac{10r}{12} - \frac{6}{12}$
$s = \frac{5r}{6} - \frac{1}{2}$

STEP 5

Verification is optional in this context, as the solution is expressed in terms of $r$ .
The solution for $s$ is:
$s = \frac{5r}{6} - \frac{1}{2}$

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QuestionSolve for sss. −10r+12s=−6s=[]\begin{array}{l} -10 r+12 s=-6 \\ s=[] \end{array}−10r+12s=−6s=[]​

Studdy Solution

STEP 1

1. The equation −10r+12s=−6 -10r + 12s = -6 −10r+12s=−6 is a linear equation in terms of s s s.2. We need to isolate s s s on one side of the equation.3. The equation involves basic algebraic operations such as addition, subtraction, and division.

STEP 2

1. Rearrange the equation to isolate terms involving s s s.2. Solve for s s s by performing algebraic operations.3. Verify the solution by substituting back into the original equation if necessary.

STEP 3

Start with the given equation:−10r+12s=−6 -10r + 12s = -6 −10r+12s=−6Our goal is to isolate s s s. First, move the term involving r r r to the other side of the equation by adding 10r 10r 10r to both sides:12s=10r−6 12s = 10r - 6 12s=10r−6

STEP 4

Now, solve for s s s by dividing every term by 12:s=10r−612 s = \frac{10r - 6}{12} s=1210r−6​Simplify the expression if possible:s=10r12−612 s = \frac{10r}{12} - \frac{6}{12} s=1210r​−126​s=5r6−12 s = \frac{5r}{6} - \frac{1}{2} s=65r​−21​

STEP 5

Verification is optional in this context, as the solution is expressed in terms of r r r.The solution for s s s is:s=5r6−12 s = \frac{5r}{6} - \frac{1}{2} s=65r​−21​

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Studdy solves anything!

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

QuestionSolve for $s$ . $\begin{array}{l} -10 r+12 s=-6 \\ s=[] \end{array}$

1. The equation $-10r + 12s = -6$ is a linear equation in terms of $s$ .
2. We need to isolate $s$ on one side of the equation.
3. The equation involves basic algebraic operations such as addition, subtraction, and division.

1. Rearrange the equation to isolate terms involving $s$ .
2. Solve for $s$ by performing algebraic operations.
3. Verify the solution by substituting back into the original equation if necessary.

Start with the given equation:
$-10r + 12s = -6$
Our goal is to isolate $s$ . First, move the term involving $r$ to the other side of the equation by adding $10r$ to both sides:
$12s = 10r - 6$

Now, solve for $s$ by dividing every term by 12:
$s = \frac{10r - 6}{12}$
Simplify the expression if possible:
$s = \frac{10r}{12} - \frac{6}{12}$
$s = \frac{5r}{6} - \frac{1}{2}$

Verification is optional in this context, as the solution is expressed in terms of $r$ .
The solution for $s$ is:
$s = \frac{5r}{6} - \frac{1}{2}$