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Math

Question Find the value of yy in the linear equation 2x+3y=122x + 3y = 12.

Studdy Solution

STEP 1

Assumptions
1. The given equation is 2x+3y=122x + 3y = 12.
2. We need to solve for yy in terms of xx.

STEP 2

Isolate the term containing yy on one side of the equation. To do this, we will subtract 2x2x from both sides of the equation.
2x+3y−2x=12−2x2x + 3y - 2x = 12 - 2x

STEP 3

Simplify the equation by removing 2x2x from the left side.
3y=12−2x3y = 12 - 2x

STEP 4

Now, divide both sides of the equation by 3 to solve for yy.
3y3=12−2x3\frac{3y}{3} = \frac{12 - 2x}{3}

STEP 5

Simplify the equation by performing the division.
y=123−2x3y = \frac{12}{3} - \frac{2x}{3}

STEP 6

Complete the division to find the value of yy.
y=4−2x3y = 4 - \frac{2x}{3}
The solution for yy in terms of xx is y=4−2x3y = 4 - \frac{2x}{3}.

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