Math

QuestionSolve for xx: 23x+14=62|3x+1|-4=6. What are the possible values of xx?

Studdy Solution

STEP 1

Assumptions1. The absolute value function is defined as x=x|x| = x for x0x \geq0 and x=x|x| = -x for x<0x <0. . The equation to solve is 3x+14=6|3x+1|-4=6.

STEP 2

First, we need to isolate the absolute value function. We can do this by adding4 to both sides of the equation.
2x+1=6+42|x+1| =6 +4

STEP 3

Now, simplify the right side of the equation.
23x+1=102|3x+1| =10

STEP 4

Next, we need to further isolate the absolute value function. We can do this by dividing both sides of the equation by2.
3x+1=102|3x+1| = \frac{10}{2}

STEP 5

implify the right side of the equation.
3x+1=5|3x+1| =5

STEP 6

Now, we can split the equation into two cases, one for 3x+103x+1 \geq0 and one for 3x+1<03x+1 <0.
Case1 3x+103x+1 \geq0
3x+1=53x+1 =5Case2 3x+1<03x+1 <0
(3x+1)=5-(3x+1) =5

STEP 7

Now, solve for xx in both cases.
Case1 3x+1=53x+1 =5
3x=513x =5 -1Case2 (3x+1)=5-(3x+1) =5
3x1=5-3x -1 =5

STEP 8

implify both equations.
Case1 3x=43x =4
x=43x = \frac{4}{3}Case2 3x1=5-3x -1 =5
3x=5+1-3x =5 +1

STEP 9

olve for xx in the second case.
3x=6-3x =6x=63x = -\frac{6}{3}

STEP 10

implify the solution for the second case.
x=2x = -2So, the solutions for the equation 23x+4=62|3x+|-4=6 are x=43x=\frac{4}{3} and x=2x=-2.

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