Math  /  Algebra

QuestionSolve for yy in terms of xx. 3x2y=8y=\begin{array}{l} 3 x-2 y=8 \\ y=\square \end{array}

Studdy Solution

STEP 1

What is this asking? We're given an equation with xx and yy, and we need to rewrite it so yy is all alone on one side, expressed in terms of xx. Watch out! Don't forget to keep track of those negative signs!
They can be sneaky.

STEP 2

1. Isolate the term with yy.
2. Solve for yy.

STEP 3

We're starting with 3x2y=83x - 2y = 8.
Our goal here is to get yy by itself.

STEP 4

To move the 3x3x to the other side, we'll subtract 3x3x from both sides of the equation.
This gives us 3x2y3x=83x3x - 2y - 3x = 8 - 3x.
Remember, whatever we do to one side, we *must* do to the other!

STEP 5

On the left side, 3x3x3x - 3x adds to zero, leaving us with 2y-2y.
So, our equation now looks like 2y=83x-2y = 8 - 3x.
We're getting closer to having yy all alone!

STEP 6

Now, we need to get rid of that 2-2 attached to the yy.
We can do this by dividing both sides of the equation by 2-2.
This gives us 2y2=83x2\frac{-2y}{-2} = \frac{8 - 3x}{-2}.
Dividing 2-2 by 2-2 gives us 11, which is exactly what we want!

STEP 7

On the left side, we have 2y2=1y=y\frac{-2y}{-2} = 1 \cdot y = y, which is exactly what we were aiming for!
On the right side, we have 83x2\frac{8 - 3x}{-2}.
We can rewrite this as 823x2\frac{8}{-2} - \frac{3x}{-2}.
This simplifies to 4+32x-4 + \frac{3}{2}x, or 32x4\frac{3}{2}x - 4.

STEP 8

So, our final equation is y=32x4y = \frac{3}{2}x - 4.
We've successfully isolated yy and expressed it in terms of xx!

STEP 9

y=32x4y = \frac{3}{2}x - 4

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