Math  /  Algebra

QuestionSolve the equation. 3.6w=2(0.8w+12)3.6 w=2(0.8 w+12)
Enter the correct answer in the box.
Show Hints w=w= \square

Studdy Solution

STEP 1

1. The equation 3.6w=2(0.8w+12) 3.6w = 2(0.8w + 12) is a linear equation in one variable, w w .
2. The goal is to find the value of w w that satisfies the equation.
3. Basic algebraic operations, such as distribution and combining like terms, will be used.

STEP 2

1. Expand the equation by distributing the constant on the right side.
2. Simplify the equation by combining like terms.
3. Isolate the variable w w to solve for it.
4. Verify the solution by substituting it back into the original equation.

STEP 3

Start by distributing the 2 2 on the right side of the equation:
3.6w=2×0.8w+2×12 3.6w = 2 \times 0.8w + 2 \times 12
This gives:
3.6w=1.6w+24 3.6w = 1.6w + 24

STEP 4

Next, we need to get all terms involving w w on one side of the equation. Subtract 1.6w 1.6w from both sides:
3.6w1.6w=24 3.6w - 1.6w = 24
Simplify the left side:
2.0w=24 2.0w = 24

STEP 5

Now, solve for w w by dividing both sides by 2.0 2.0 :
w=242.0 w = \frac{24}{2.0}
Calculate the division:
w=12 w = 12

STEP 6

Verify the solution by substituting w=12 w = 12 back into the original equation:
Original equation:
3.6(12)=2(0.8(12)+12) 3.6(12) = 2(0.8(12) + 12)
Calculate both sides:
Left side:
3.6×12=43.2 3.6 \times 12 = 43.2
Right side:
2(0.8×12+12)=2(9.6+12)=2×21.6=43.2 2(0.8 \times 12 + 12) = 2(9.6 + 12) = 2 \times 21.6 = 43.2
Both sides are equal, confirming the solution is correct.
The solution is:
12 \boxed{12}

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