Math  /  Algebra

QuestionSolve the equation. 4(2v+3)=28-4(-2 v+3)=28

Studdy Solution

STEP 1

What is this asking? We need to find the value of vv that makes the equation 4(2v+3)=28-4(-2v + 3) = 28 true. Watch out! Be careful with the signs when distributing!
A negative times a negative is a positive, and a negative times a positive is a negative.

STEP 2

1. Distribute
2. Isolate the term with vv
3. Solve for vv

STEP 3

Alright, let's **kick things off** by distributing that 4-4 into the parentheses!
Remember, distributing means multiplying the 4-4 by each term inside the parentheses.

STEP 4

4(2v)+(4)3=28-4 \cdot (-2v) + (-4) \cdot 3 = 28 So, 4-4 times 2v-2v gives us 8v8v, and 4-4 times 33 gives us 12-12.

STEP 5

Our equation now looks like this: 8v12=288v - 12 = 28 Much cleaner, right?

STEP 6

Next, we want to get that vv term all by itself.
Let's **add** 1212 to **both sides** of the equation to move that 12-12 over to the right.
Remember, what we do to one side, we *must* do to the other to keep things balanced!

STEP 7

8v12+12=28+128v - 12 + 12 = 28 + 12 Notice how 12+12-12 + 12 becomes zero.
This is what we wanted.

STEP 8

Now we have: 8v=408v = 40 We're almost there!

STEP 9

Finally, to **get** v\boldsymbol{v} **all alone**, we need to **divide both sides** of the equation by 88.

STEP 10

8v8=408\frac{8v}{8} = \frac{40}{8} Since 88\frac{8}{8} is 11, we have 11 times vv on the left side, which is just vv.
Perfect!

STEP 11

And on the right side, 408\frac{40}{8} gives us 55.

STEP 12

v=5v = 5 Boom! We found it!

STEP 13

The solution to the equation 4(2v+3)=28-4(-2v + 3) = 28 is v=5v = 5.

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