QuestionSolve the equation: $4(2-5 x)+3=2 x$

Studdy Solution

STEP 1

Assumptions1. The given equation is $4(-5x)+3=x$ . We are solving for $x$

STEP 2

First, we need to distribute the $4$ in the equation.
$4(2-5x)+=2x$ Becomes $8-20x+=2x$

STEP 3

Combine like terms on the left side of the equation.
$8 +3 -20x =2x$ Becomes $11 -20x =2x$

STEP 4

Now, we need to get all the $x$ terms on one side and the constants on the other side. Add $20x$ to both sides of the equation.
$11 -20x +20x =2x +20x$ Becomes $11 =22x$

STEP 5

Finally, we can solve for $x$ by dividing both sides of the equation by $22$ .
$\frac{11}{22} = \frac{22x}{22}$ Becomes $x = \frac{1}{2}$ So, the solution to the equation $4(2-5x)+3=2x$ is $x = \frac{1}{2}$ .

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QuestionSolve the equation: $4(2-5 x)+3=2 x$

Studdy Solution

STEP 1

Assumptions1. The given equation is $4(-5x)+3=x$ . We are solving for $x$

STEP 2

First, we need to distribute the $4$ in the equation.
$4(2-5x)+=2x$ Becomes $8-20x+=2x$

STEP 3

Combine like terms on the left side of the equation.
$8 +3 -20x =2x$ Becomes $11 -20x =2x$

STEP 4

Now, we need to get all the $x$ terms on one side and the constants on the other side. Add $20x$ to both sides of the equation.
$11 -20x +20x =2x +20x$ Becomes $11 =22x$

STEP 5

Finally, we can solve for $x$ by dividing both sides of the equation by $22$ .
$\frac{11}{22} = \frac{22x}{22}$ Becomes $x = \frac{1}{2}$ So, the solution to the equation $4(2-5x)+3=2x$ is $x = \frac{1}{2}$ .

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QuestionSolve the equation: 4(2−5x)+3=2x4(2-5 x)+3=2 x4(2−5x)+3=2x

Studdy Solution

STEP 1

Assumptions1. The given equation is 4(−5x)+3=x4(-5x)+3=x4(−5x)+3=x . We are solving for xxx

STEP 2

First, we need to distribute the 444 in the equation.4(2−5x)+=2x4(2-5x)+=2x4(2−5x)+=2xBecomes8−20x+=2x8-20x+=2x8−20x+=2x

STEP 3

Combine like terms on the left side of the equation.8+3−20x=2x8 +3 -20x =2x8+3−20x=2xBecomes11−20x=2x11 -20x =2x11−20x=2x

STEP 4

Now, we need to get all the xxx terms on one side and the constants on the other side. Add 20x20x20x to both sides of the equation.11−20x+20x=2x+20x11 -20x +20x =2x +20x11−20x+20x=2x+20xBecomes11=22x11 =22x11=22x

STEP 5

Finally, we can solve for xxx by dividing both sides of the equation by 222222.1122=22x22\frac{11}{22} = \frac{22x}{22}2211​=2222x​Becomesx=12x = \frac{1}{2}x=21​So, the solution to the equation 4(2−5x)+3=2x4(2-5x)+3=2x4(2−5x)+3=2x is x=12x = \frac{1}{2}x=21​.

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QuestionSolve the equation: $4(2-5 x)+3=2 x$

Assumptions1. The given equation is $4(-5x)+3=x$ . We are solving for $x$

First, we need to distribute the $4$ in the equation.
$4(2-5x)+=2x$ Becomes $8-20x+=2x$

Combine like terms on the left side of the equation.
$8 +3 -20x =2x$ Becomes $11 -20x =2x$

Now, we need to get all the $x$ terms on one side and the constants on the other side. Add $20x$ to both sides of the equation.
$11 -20x +20x =2x +20x$ Becomes $11 =22x$

Finally, we can solve for $x$ by dividing both sides of the equation by $22$ .
$\frac{11}{22} = \frac{22x}{22}$ Becomes $x = \frac{1}{2}$ So, the solution to the equation $4(2-5x)+3=2x$ is $x = \frac{1}{2}$ .