QuestionSolve the linear equation: $6z + 4 = 6(z + 3) - 14$ .

Studdy Solution

STEP 1

Assumptions1. The equation is a linear equation in one variable, z. . The equation is given as $6z +4 =6(z +3) -14$

STEP 2

First, we need to distribute the6 on the right side of the equation to both terms inside the parentheses.
$6z +4 =6z +18 -14$

STEP 3

Now, simplify the right side of the equation.
$6z + =6z +$

STEP 4

Subtract $6z$ from both sides of the equation to isolate the variable on one side.
$6z -6z +4 =6z -6z +4$

STEP 5

implify the equation.
$4 =4$

STEP 6

This equation is always true, which means that the original equation has infinitely many solutions. Any value of $z$ will satisfy the equation.

Was this helpful?

QuestionSolve the linear equation: $6z + 4 = 6(z + 3) - 14$ .

Studdy Solution

STEP 1

Assumptions1. The equation is a linear equation in one variable, z. . The equation is given as $6z +4 =6(z +3) -14$

STEP 2

First, we need to distribute the6 on the right side of the equation to both terms inside the parentheses.
$6z +4 =6z +18 -14$

STEP 3

Now, simplify the right side of the equation.
$6z + =6z +$

STEP 4

Subtract $6z$ from both sides of the equation to isolate the variable on one side.
$6z -6z +4 =6z -6z +4$

STEP 5

implify the equation.
$4 =4$

STEP 6

This equation is always true, which means that the original equation has infinitely many solutions. Any value of $z$ will satisfy the equation.

Get Studdy

Studdy solves anything!

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

QuestionSolve the linear equation: 6z+4=6(z+3)−146z + 4 = 6(z + 3) - 146z+4=6(z+3)−14.

Studdy Solution

STEP 1

Assumptions1. The equation is a linear equation in one variable, z. . The equation is given as 6z+4=6(z+3)−146z +4 =6(z +3) -146z+4=6(z+3)−14

STEP 2

First, we need to distribute the6 on the right side of the equation to both terms inside the parentheses.6z+4=6z+18−146z +4 =6z +18 -146z+4=6z+18−14

STEP 3

Now, simplify the right side of the equation.6z+=6z+6z + =6z +6z+=6z+

STEP 4

Subtract 6z6z6z from both sides of the equation to isolate the variable on one side.6z−6z+4=6z−6z+46z -6z +4 =6z -6z +46z−6z+4=6z−6z+4

STEP 5

implify the equation.4=44 =44=4

STEP 6

This equation is always true, which means that the original equation has infinitely many solutions. Any value of zzz will satisfy the equation.

Get Studdy

Studdy solves anything!

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

QuestionSolve the linear equation: $6z + 4 = 6(z + 3) - 14$ .

Assumptions1. The equation is a linear equation in one variable, z. . The equation is given as $6z +4 =6(z +3) -14$

First, we need to distribute the6 on the right side of the equation to both terms inside the parentheses.
$6z +4 =6z +18 -14$

Now, simplify the right side of the equation.
$6z + =6z +$

Subtract $6z$ from both sides of the equation to isolate the variable on one side.
$6z -6z +4 =6z -6z +4$

implify the equation.
$4 =4$

This equation is always true, which means that the original equation has infinitely many solutions. Any value of $z$ will satisfy the equation.