PROBLEM
Solve the equation 8tan(4θ)+3=11 for a value of θ in the first quadrant. Give your answer in radians and degrees.
θ= □ radians, to 4 decimal places or □ degrees.
STEP 1
1. The equation 8tan(4θ)+3=11 is trigonometric.
2. We are solving for θ in the first quadrant, where 0<θ<2π.
3. We will convert the solution from radians to degrees.
STEP 2
1. Isolate the trigonometric function tan(4θ).
2. Solve for 4θ.
3. Solve for θ.
4. Convert θ from radians to degrees.
STEP 3
Subtract 3 from both sides of the equation to isolate the term with the tangent function:
8tan(4θ)+3=11 8tan(4θ)=11−3 8tan(4θ)=8
STEP 4
Divide both sides by 8 to solve for tan(4θ):
tan(4θ)=88 tan(4θ)=1
STEP 5
Find 4θ by taking the arctangent of both sides. Since tan(4π)=1, we have:
4θ=4π Solve for θ by dividing both sides by 4:
θ=4π×41 θ=16π
SOLUTION
Convert θ from radians to degrees. We know that 180∘=π radians, so:
θ=16π×π180∘ θ=16180∘ θ=11.25∘ The value of θ is:
θ=16π radians, or 11.25∘
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