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Math

Math Snap

PROBLEM

atic by factoring.
2x2+9x1=2x72 x^{2}+9 x-1=2 x-7

STEP 1

What is this asking?
We need to find the values of xx that make the equation 2x2+9x1=2x72x^2 + 9x - 1 = 2x - 7 true!
Watch out!
Don't forget to set the equation to zero before factoring.
It's a super common mistake, so let's be extra careful!

STEP 2

1. Rewrite the equation
2. Factor the quadratic
3. Solve for x

STEP 3

First, we subtract 2x2x from both sides of the equation.
We do this to start grouping like terms together!
This gives us:
2x2+9x2x1=2x2x72x^2 + 9x - 2x - 1 = 2x - 2x - 7 2x2+7x1=72x^2 + 7x - 1 = -7Now, let's add 7 to both sides to completely set the equation to zero:
2x2+7x1+7=7+72x^2 + 7x - 1 + 7 = -7 + 7 2x2+7x+6=02x^2 + 7x + 6 = 0Awesome! Now we have a quadratic equation set to zero, ready for factoring!

STEP 4

We're looking for two numbers that multiply to (26)=12(2 \cdot 6) = \textbf{12} and add up to 7\textbf{7}.
Let's think... How about 3 and 4?
Yes, that works! 34=123 \cdot 4 = 12 and 3+4=73 + 4 = 7.
Perfect!

STEP 5

Now, we rewrite the middle term using our magic numbers, 3 and 4:
2x2+3x+4x+6=02x^2 + 3x + 4x + 6 = 0

STEP 6

Let's group the first two terms and the last two terms:
(2x2+3x)+(4x+6)=0(2x^2 + 3x) + (4x + 6) = 0 Now, we factor out the greatest common factor from each group.
From the first group, we can factor out xx, and from the second group, we can factor out 2:
x(2x+3)+2(2x+3)=0x(2x + 3) + 2(2x + 3) = 0 Notice that we have the same expression, (2x+3)(2x + 3), in both terms.
Let's factor that out!
(2x+3)(x+2)=0(2x + 3)(x + 2) = 0 Boom! We've factored our quadratic!

STEP 7

Now, we set each factor equal to zero and solve for xx.
This is because if either factor is zero, the entire expression will be zero.
First factor:
2x+3=02x + 3 = 0 2x=32x = -3x=32x = -\frac{3}{2}Second factor:
x+2=0x + 2 = 0 x=2x = -2

SOLUTION

The solutions to the equation 2x2+9x1=2x72x^2 + 9x - 1 = 2x - 7 are x=32x = -\frac{3}{2} and x=2x = -2!

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