QuestionSolve for $g$ and $h$ in the equation $g(y h+b)=e+q$ . Find $g=$ and $h=$ .

Studdy Solution

STEP 1

Assumptions1. The equation given is $g(yh+b)=e+q$ . We need to solve for $g$ and $h$
3. All variables represent real numbers

STEP 2

First, we will solve for $g$ . We can do this by isolating $g$ on one side of the equation.
$g = \frac{e+q}{yh+b}$

STEP 3

Now, we will solve for $h$ . To do this, we first need to isolate the term containing $h$ .
$yh+b = \frac{e+q}{g}$

STEP 4

Subtract $b$ from both sides of the equation to isolate $yh$ .
$yh = \frac{e+q}{g} - b$

STEP 5

Finally, divide both sides of the equation by $y$ to solve for $h$ .
$h = \frac{\frac{e+q}{g} - b}{y}$ Thus, the solutions are $g = \frac{e+q}{yh+b}$ and $h = \frac{\frac{e+q}{g} - b}{y}$ .

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QuestionSolve for $g$ and $h$ in the equation $g(y h+b)=e+q$ . Find $g=$ and $h=$ .

Studdy Solution

STEP 1

Assumptions1. The equation given is $g(yh+b)=e+q$ . We need to solve for $g$ and $h$
3. All variables represent real numbers

STEP 2

First, we will solve for $g$ . We can do this by isolating $g$ on one side of the equation.
$g = \frac{e+q}{yh+b}$

STEP 3

Now, we will solve for $h$ . To do this, we first need to isolate the term containing $h$ .
$yh+b = \frac{e+q}{g}$

STEP 4

Subtract $b$ from both sides of the equation to isolate $yh$ .
$yh = \frac{e+q}{g} - b$

STEP 5

Finally, divide both sides of the equation by $y$ to solve for $h$ .
$h = \frac{\frac{e+q}{g} - b}{y}$ Thus, the solutions are $g = \frac{e+q}{yh+b}$ and $h = \frac{\frac{e+q}{g} - b}{y}$ .

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QuestionSolve for ggg and hhh in the equation g(yh+b)=e+qg(y h+b)=e+qg(yh+b)=e+q. Find g=g=g= and h=h=h=.

Studdy Solution

STEP 1

Assumptions1. The equation given is g(yh+b)=e+qg(yh+b)=e+qg(yh+b)=e+q . We need to solve for ggg and hhh3. All variables represent real numbers

STEP 2

First, we will solve for ggg. We can do this by isolating ggg on one side of the equation.g=e+qyh+bg = \frac{e+q}{yh+b}g=yh+be+q​

STEP 3

Now, we will solve for hhh. To do this, we first need to isolate the term containing hhh.yh+b=e+qgyh+b = \frac{e+q}{g}yh+b=ge+q​

STEP 4

Subtract bbb from both sides of the equation to isolate yhyhyh.yh=e+qg−byh = \frac{e+q}{g} - byh=ge+q​−b

STEP 5

Finally, divide both sides of the equation by yyy to solve for hhh.h=e+qg−byh = \frac{\frac{e+q}{g} - b}{y}h=yge+q​−b​Thus, the solutions are g=e+qyh+bg = \frac{e+q}{yh+b}g=yh+be+q​ and h=e+qg−byh = \frac{\frac{e+q}{g} - b}{y}h=yge+q​−b​.

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QuestionSolve for $g$ and $h$ in the equation $g(y h+b)=e+q$ . Find $g=$ and $h=$ .

Assumptions1. The equation given is $g(yh+b)=e+q$ . We need to solve for $g$ and $h$
3. All variables represent real numbers

First, we will solve for $g$ . We can do this by isolating $g$ on one side of the equation.
$g = \frac{e+q}{yh+b}$

Now, we will solve for $h$ . To do this, we first need to isolate the term containing $h$ .
$yh+b = \frac{e+q}{g}$

Subtract $b$ from both sides of the equation to isolate $yh$ .
$yh = \frac{e+q}{g} - b$

Finally, divide both sides of the equation by $y$ to solve for $h$ .
$h = \frac{\frac{e+q}{g} - b}{y}$ Thus, the solutions are $g = \frac{e+q}{yh+b}$ and $h = \frac{\frac{e+q}{g} - b}{y}$ .