Math

QuestionSolve and verify the equation: 2y+4=33y3-2y + 4 = 33y - 3.

Studdy Solution

STEP 1

Assumptions1. The equation is linear in nature. . The variable y is real.

STEP 2

First, we need to bring all the terms involving y to one side of the equation. We can do this by adding2y to both sides of the equation.
2y+2y+4=33y+2y-2y +2y +4 =33y - +2y

STEP 3

implify the equation.
=35y3 =35y -3

STEP 4

Next, we need to isolate the y term. We can do this by adding3 to both sides of the equation.
4+3=35y3+34 +3 =35y -3 +3

STEP 5

implify the equation.
7=35y7 =35y

STEP 6

Finally, we need to solve for y. We can do this by dividing both sides of the equation by35.
35=35y35\frac{}{35} = \frac{35y}{35}

STEP 7

implify the equation.
y=15y = \frac{1}{5}

STEP 8

Now, we need to check our solution. We can do this by substituting y =1/5 into the original equation.
2(15)+4=33(15)3-2(\frac{1}{5}) +4 =33(\frac{1}{5}) -3

STEP 9

implify the equation.
25+4=3353-\frac{2}{5} +4 = \frac{33}{5} -3

STEP 10

Convert the whole numbers to fractions with denominator5.
25+205=335155-\frac{2}{5} + \frac{20}{5} = \frac{33}{5} - \frac{15}{5}

STEP 11

implify the equation.
185=185\frac{18}{5} = \frac{18}{5}Since both sides of the equation are equal, our solution is correct. The solution to the equation is y =/5.

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