Question Solve $x=2Y+6z-y^2$ for $x$ given $y=6$ and $z=2$ . A) 12 B) 11 C) -11 D) -12

Studdy Solution

STEP 1

Assumptions
1. The equation is given by $x = 2Y + 6z - y^2$ .
2. The value of $y$ is given as $y = 6$ .
3. The value of $z$ is given as $z = 2$ .
4. We need to solve for $x$ using the given values of $y$ and $z$ .

STEP 2

First, we substitute the given value of $y$ into the equation.
$x = 2Y + 6z - y^2$
$x = 2(6) + 6z - 6^2$

STEP 3

Next, we substitute the given value of $z$ into the equation.
$x = 2(6) + 6(2) - 6^2$

STEP 4

Now, we perform the arithmetic operations according to the order of operations (PEMDAS/BODMAS).
$x = 12 + 12 - 36$

STEP 5

Combine the like terms to find the value of $x$ .
$x = 24 - 36$

STEP 6

Subtract $36$ from $24$ to get the final value of $x$ .
$x = -12$
The solution is $x = -12$ , which corresponds to option D.

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Question Solve $x=2Y+6z-y^2$ for $x$ given $y=6$ and $z=2$ . A) 12 B) 11 C) -11 D) -12

Studdy Solution

STEP 1

Assumptions
1. The equation is given by $x = 2Y + 6z - y^2$ .
2. The value of $y$ is given as $y = 6$ .
3. The value of $z$ is given as $z = 2$ .
4. We need to solve for $x$ using the given values of $y$ and $z$ .

STEP 2

First, we substitute the given value of $y$ into the equation.
$x = 2Y + 6z - y^2$
$x = 2(6) + 6z - 6^2$

STEP 3

Next, we substitute the given value of $z$ into the equation.
$x = 2(6) + 6(2) - 6^2$

STEP 4

Now, we perform the arithmetic operations according to the order of operations (PEMDAS/BODMAS).
$x = 12 + 12 - 36$

STEP 5

Combine the like terms to find the value of $x$ .
$x = 24 - 36$

STEP 6

Subtract $36$ from $24$ to get the final value of $x$ .
$x = -12$
The solution is $x = -12$ , which corresponds to option D.

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Question Solve x=2Y+6z−y2x=2Y+6z-y^2x=2Y+6z−y2 for xxx given y=6y=6y=6 and z=2z=2z=2. A) 12 B) 11 C) -11 D) -12

Studdy Solution

STEP 1

Assumptions1. The equation is given by x=2Y+6z−y2x = 2Y + 6z - y^2x=2Y+6z−y2.2. The value of yyy is given as y=6y = 6y=6.3. The value of zzz is given as z=2z = 2z=2.4. We need to solve for xxx using the given values of yyy and zzz.

STEP 2

First, we substitute the given value of yyy into the equation.x=2Y+6z−y2x = 2Y + 6z - y^2x=2Y+6z−y2x=2(6)+6z−62x = 2(6) + 6z - 6^2x=2(6)+6z−62

STEP 3

Next, we substitute the given value of zzz into the equation.x=2(6)+6(2)−62x = 2(6) + 6(2) - 6^2x=2(6)+6(2)−62

STEP 4

Now, we perform the arithmetic operations according to the order of operations (PEMDAS/BODMAS).x=12+12−36x = 12 + 12 - 36x=12+12−36

STEP 5

Combine the like terms to find the value of xxx.x=24−36x = 24 - 36x=24−36

STEP 6

Subtract 363636 from 242424 to get the final value of xxx.x=−12x = -12x=−12The solution is x=−12x = -12x=−12, which corresponds to option D.

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Question Solve $x=2Y+6z-y^2$ for $x$ given $y=6$ and $z=2$ . A) 12 B) 11 C) -11 D) -12

Assumptions
1. The equation is given by $x = 2Y + 6z - y^2$ .
2. The value of $y$ is given as $y = 6$ .
3. The value of $z$ is given as $z = 2$ .
4. We need to solve for $x$ using the given values of $y$ and $z$ .

First, we substitute the given value of $y$ into the equation.
$x = 2Y + 6z - y^2$
$x = 2(6) + 6z - 6^2$

Next, we substitute the given value of $z$ into the equation.
$x = 2(6) + 6(2) - 6^2$

Now, we perform the arithmetic operations according to the order of operations (PEMDAS/BODMAS).
$x = 12 + 12 - 36$

Combine the like terms to find the value of $x$ .
$x = 24 - 36$

Subtract $36$ from $24$ to get the final value of $x$ .
$x = -12$
The solution is $x = -12$ , which corresponds to option D.