Question Solve the linear equation $7k + mj = kr + 4m + 3$ for $m$ .

Studdy Solution

STEP 1

Assumptions1. We are given the equation $7k + mj = kr +4m +3$ . We are asked to solve for $m$

STEP 2

First, we need to gather all terms involving $m$ on one side of the equation. We can do this by subtracting $mj$ and $4m$ from both sides of the equation.
$7k - kr = mj -4m +$

STEP 3

Now, we can factor out $m$ from the right side of the equation.
$7k - kr = m(j -) +3$

STEP 4

Next, we need to isolate $m$ by subtracting $3$ from both sides of the equation.
$7k - kr -3 = m(j -4)$

STEP 5

Finally, we can solve for $m$ by dividing both sides of the equation by $j -4$ .
$m = \frac{7k - kr -3}{j -4}$ So, the solution for $m$ is $m = \frac{7k - kr -3}{j -4}$ .

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Question Solve the linear equation $7k + mj = kr + 4m + 3$ for $m$ .

Studdy Solution

STEP 1

Assumptions1. We are given the equation $7k + mj = kr +4m +3$ . We are asked to solve for $m$

STEP 2

First, we need to gather all terms involving $m$ on one side of the equation. We can do this by subtracting $mj$ and $4m$ from both sides of the equation.
$7k - kr = mj -4m +$

STEP 3

Now, we can factor out $m$ from the right side of the equation.
$7k - kr = m(j -) +3$

STEP 4

Next, we need to isolate $m$ by subtracting $3$ from both sides of the equation.
$7k - kr -3 = m(j -4)$

STEP 5

Finally, we can solve for $m$ by dividing both sides of the equation by $j -4$ .
$m = \frac{7k - kr -3}{j -4}$ So, the solution for $m$ is $m = \frac{7k - kr -3}{j -4}$ .

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Question Solve the linear equation 7k+mj=kr+4m+37k + mj = kr + 4m + 37k+mj=kr+4m+3 for mmm.

Studdy Solution

STEP 1

Assumptions1. We are given the equation 7k+mj=kr+4m+37k + mj = kr +4m +37k+mj=kr+4m+3 . We are asked to solve for mmm

STEP 2

First, we need to gather all terms involving mmm on one side of the equation. We can do this by subtracting mjmjmj and 4m4m4m from both sides of the equation.7k−kr=mj−4m+7k - kr = mj -4m +7k−kr=mj−4m+

STEP 3

Now, we can factor out mmm from the right side of the equation.7k−kr=m(j−)+37k - kr = m(j -) +37k−kr=m(j−)+3

STEP 4

Next, we need to isolate mmm by subtracting 333 from both sides of the equation.7k−kr−3=m(j−4)7k - kr -3 = m(j -4)7k−kr−3=m(j−4)

STEP 5

Finally, we can solve for mmm by dividing both sides of the equation by j−4j -4j−4.m=7k−kr−3j−4m = \frac{7k - kr -3}{j -4}m=j−47k−kr−3​So, the solution for mmm is m=7k−kr−3j−4m = \frac{7k - kr -3}{j -4}m=j−47k−kr−3​.

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Question Solve the linear equation $7k + mj = kr + 4m + 3$ for $m$ .

Assumptions1. We are given the equation $7k + mj = kr +4m +3$ . We are asked to solve for $m$

First, we need to gather all terms involving $m$ on one side of the equation. We can do this by subtracting $mj$ and $4m$ from both sides of the equation.
$7k - kr = mj -4m +$

Now, we can factor out $m$ from the right side of the equation.
$7k - kr = m(j -) +3$

Next, we need to isolate $m$ by subtracting $3$ from both sides of the equation.
$7k - kr -3 = m(j -4)$

Finally, we can solve for $m$ by dividing both sides of the equation by $j -4$ .
$m = \frac{7k - kr -3}{j -4}$ So, the solution for $m$ is $m = \frac{7k - kr -3}{j -4}$ .