Math

QuestionSolve the equation x224x+143=0x^{2}-24 x+143=0.

Studdy Solution

STEP 1

Assumptions1. The given equation is a quadratic equation of the form ax+bx+c=0ax^ + bx + c =0 . We are asked to solve for xx

STEP 2

The quadratic formula is used to solve equations of the form ax2+bx+c=0ax^2 + bx + c =0. The formula is given byx=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 -4ac}}{2a}

STEP 3

Identify the coefficients aa, bb, and cc from the given equation x224x+143=0x^{2}-24x+143=0. Here, a=1a=1, b=24b=-24, and c=143c=143.

STEP 4

Substitute the values of aa, bb, and cc into the quadratic formula.
x=(24)±(24)24114321x = \frac{-(-24) \pm \sqrt{(-24)^2 -4*1*143}}{2*1}

STEP 5

implify the equation.
x=24±5765722x = \frac{24 \pm \sqrt{576 -572}}{2}

STEP 6

Further simplify the equation.
x=24±42x = \frac{24 \pm \sqrt{4}}{2}

STEP 7

Take the square root of4.
x=24±22x = \frac{24 \pm2}{2}

STEP 8

olve for xx by using the plus and minus signs separately.
x=24+22orx=2422x = \frac{24 +2}{2} \quad or \quad x = \frac{24 -2}{2}

STEP 9

implify to find the two solutions for xx.
x=13orx=11x =13 \quad or \quad x =11The solutions to the equation x224x+143=x^{2}-24x+143= are x=13x =13 and x=11x =11.

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