Math

QuestionSolve: Isqrt[3]{x+28} - Isqrt[3]{x-28} = 2. Find x.

Studdy Solution

STEP 1

Assumptions1. The problem is to solve the equation x+283x283=\sqrt[3]{x+28}-\sqrt[3]{x-28}= for xx. . The cube root function, x3\sqrt[3]{x}, is the inverse of the cubing function, x3x^3.

STEP 2

First, we can isolate one of the cube root terms. Let's isolate x+28\sqrt[]{x+28}.
x+28=x28+2\sqrt[]{x+28} = \sqrt[]{x-28} +2

STEP 3

Next, we can cube both sides of the equation to eliminate the cube root. This is possible because the cube and cube root functions are inverses.
(x+283)3=(x283+2)3(\sqrt[3]{x+28})^3 = (\sqrt[3]{x-28} +2)^3

STEP 4

implify both sides of the equation.
x+28=(x28+2)3x+28 = (x-28 +2)^3

STEP 5

implify the right side of the equation using the binomial cube formula, (a+b)3=a3+3a2b+3ab2+b3(a+b)^3 = a^3 +3a^2b +3ab^2 + b^3.
x+28=(x28)3+3(x28)2(2)+3(x28)(2)2+23x+28 = (x-28)^3 +3(x-28)^2(2) +3(x-28)(2)^2 +2^3

STEP 6

implify the right side of the equation.
x+28=(x28)3+6(x28)2+12(x28)+8x+28 = (x-28)^3 +6(x-28)^2 +12(x-28) +8

STEP 7

Expand and simplify the right side of the equation.
x+28=x384x2+2352x21952+6x2336x+2352+12x336+x+28 = x^3 -84x^2 +2352x -21952 +6x^2 -336x +2352 +12x -336 +

STEP 8

Combine like terms on the right side of the equation.
x+28=x378x2+2376x19692x+28 = x^3 -78x^2 +2376x -19692

STEP 9

Subtract xx and 2828 from both sides of the equation to set it equal to zero.
x378x2+2375x19720=x^3 -78x^2 +2375x -19720 =

STEP 10

Now, we need to solve this cubic equation. It's not easy to factor, so we will use the Cardano's method for solving cubic equations, or use a calculator or software that can solve cubic equations.
The solution to this equation is approximately x56.44x \approx56.44.

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