Math  /  Algebra

QuestionStudent James, Quinton 5t2(t+1)=t105 t-2(t+1)=t-10 t=3t=-3 t=4t=-4 t=2t=-2 t=12t=-12

Studdy Solution

STEP 1

1. We are given the equation 5t2(t+1)=t10 5t - 2(t+1) = t - 10 .
2. We need to solve for t t .
3. We will check which of the provided options for t t satisfy the equation.

STEP 2

1. Simplify the equation.
2. Solve for t t .
3. Verify the solution against the given options.

STEP 3

Simplify the equation 5t2(t+1)=t10 5t - 2(t+1) = t - 10 :
First, distribute the 2-2 across the terms inside the parentheses:
5t2(t+1)=5t2t2 5t - 2(t + 1) = 5t - 2t - 2
This simplifies to:
3t2 3t - 2
So the equation becomes:
3t2=t10 3t - 2 = t - 10

STEP 4

Solve for t t by isolating t t on one side of the equation:
Subtract t t from both sides:
3tt2=10 3t - t - 2 = -10
This simplifies to:
2t2=10 2t - 2 = -10
Add 2 to both sides:
2t=8 2t = -8
Divide both sides by 2:
t=4 t = -4

STEP 5

Verify the solution against the given options:
The options are t=3 t = -3 , t=4 t = -4 , t=2 t = -2 , t=12 t = -12 .
The solution t=4 t = -4 matches one of the given options.
The correct solution is 4 \boxed{-4} .

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