Math  /  Data & Statistics

QuestionSuppose a box contains 2 blue, 2 red, 3 purple, and 3 green pencils.
Find P(P( not red|not green).

Studdy Solution

STEP 1

1. The box contains a total of 10 pencils: 2 blue, 2 red, 3 purple, and 3 green.
2. We are looking for the probability of selecting a pencil that is not red given that it is not green.

STEP 2

1. Determine the total number of pencils that are not green.
2. Determine the number of pencils that are not red and not green.
3. Calculate the conditional probability.

STEP 3

Count the total number of pencils that are not green. Since there are 3 green pencils, the remaining pencils are:
103=7 10 - 3 = 7

STEP 4

Count the number of pencils that are neither red nor green. The pencils that are not red are blue and purple. There are:
- 2 blue pencils - 3 purple pencils
Thus, the total number of pencils that are not red and not green is:
2+3=5 2 + 3 = 5

STEP 5

Calculate the conditional probability P(not rednot green) P(\text{not red} \mid \text{not green}) using the formula:
P(not rednot green)=Number of pencils that are not red and not greenTotal number of pencils that are not green P(\text{not red} \mid \text{not green}) = \frac{\text{Number of pencils that are not red and not green}}{\text{Total number of pencils that are not green}}
Substitute the values:
P(not rednot green)=57 P(\text{not red} \mid \text{not green}) = \frac{5}{7}
The probability is:
57 \boxed{\frac{5}{7}}

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