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PROBLEM

Suppose that a simple random sample of size n=315n=315 selected from a population has x=185x=185 successes. Calculate the margin of error for a 95%95 \% confidence interval for the proportion of successes for the population, pp.
Compute the sample proportion, p^\hat{p}, standard error estimate, SE, critical value, zz, and the margin of error, mm. Use a zz-distribution table to determine the critical value. Give all of your answers to three decimal places except give the critical value, zz, to two decimal places.
p^=\hat{p}= \square
SE=\mathrm{SE}= \square
z=z= \square
m=m= \square

STEP 1

1. The sample size n=315 n = 315 .
2. The number of successes x=185 x = 185 .
3. We are using a 95% 95\% confidence interval.
4. The population is large enough for the Central Limit Theorem to apply.

STEP 2

1. Calculate the sample proportion p^\hat{p}.
2. Calculate the standard error estimate SE\mathrm{SE}.
3. Determine the critical value zz for a 95%95\% confidence interval.
4. Calculate the margin of error mm.

STEP 3

Calculate the sample proportion p^\hat{p}:
p^=xn=185315\hat{p} = \frac{x}{n} = \frac{185}{315} p^0.587\hat{p} \approx 0.587

STEP 4

Calculate the standard error estimate SE\mathrm{SE}:
SE=p^(1p^)n=0.587×(10.587)315\mathrm{SE} = \sqrt{\frac{\hat{p}(1 - \hat{p})}{n}} = \sqrt{\frac{0.587 \times (1 - 0.587)}{315}} SE0.028\mathrm{SE} \approx 0.028

STEP 5

Determine the critical value zz for a 95%95\% confidence interval. Using a zz-distribution table, the critical value is:
z1.96z \approx 1.96

SOLUTION

Calculate the margin of error mm:
m=z×SE=1.96×0.028m = z \times \mathrm{SE} = 1.96 \times 0.028 m0.055m \approx 0.055 The sample proportion is:
p^=0.587\hat{p} = 0.587 The standard error estimate is:
SE=0.028\mathrm{SE} = 0.028 The critical value is:
z=1.96z = 1.96 The margin of error is:
m=0.055m = 0.055

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