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Math

Math Snap

PROBLEM

Suppose that you run a correlation and find the correlation coefficient is 0.325 and the regression equation is y^=7.8x21.72\hat{y}=7.8 x-21.72. The centroid of your data was (5.9,24.8)(5.9,24.8).
If the critical value is .632 , use the appropriate method to predict the yy value when xx is 3.9
\square

STEP 1

What is this asking?
Given a regression equation, correlation coefficient, critical value, and centroid, predict the y-value for a specific x-value.
Watch out!
Don't forget to consider the critical value when deciding whether to use the regression equation or the mean y-value from the centroid for prediction!

STEP 2

1. Compare the correlation coefficient and the critical value.
2. Predict the y-value.

STEP 3

The absolute value of the correlation coefficient is 0.325=0.325|0.325| = 0.325.
This tells us the strength of the linear relationship between x and y.

STEP 4

We're given a critical value of 0.6320.632.
Since 0.3250.325 is less than 0.6320.632, the correlation is not statistically significant.
This means we shouldn't use the regression equation for prediction!

STEP 5

Since the correlation isn't significant, the best prediction for any x-value is simply the average y-value, which is given by the y-coordinate of the centroid.
Our centroid is (5.9,24.8)(5.9, 24.8), so the mean y-value is **24.824.8‌.

STEP 6

Therefore, when x=3.9x = 3.9, our predicted y-value is y^=24.8\hat{y} = 24.8.

SOLUTION

The predicted y-value when x=3.9x = 3.9 is 24.824.8.

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