Math  /  Algebra

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Exponential and Logarithmic Functions 0/30 / 3 Finding the initial amount in a word problem on continuous compound..."
Susan wants to buy a bond that will mature to $6500\$ 6500 in eight years. How much should she pay for the bond now if it earns interest at a rate of 3.5%3.5 \% per year, compounded continuously? Do not round any intermediate computations, and round your answer to the nearest cent. $\$ \square

Studdy Solution

STEP 1

What is this asking? How much should Susan pay now for a bond that will be worth $6500\$6500 in eight years with continuous compounding at 3.5%3.5\% interest per year? Watch out! Don't round any numbers until the final answer!

STEP 2

1. Define the formula
2. Plug in the values
3. Solve for the initial amount

STEP 3

Alright, let's get this party started!
We're dealing with continuous compounding, so we need the formula for continuous compound interest, which is:
A=PertA = P \cdot e^{r \cdot t}
where: - AA is the **final amount** (what the bond will be worth in the future), - PP is the **initial amount** (what Susan needs to pay now), - rr is the **rate of interest** (expressed as a decimal), - tt is the **time** in years, - ee is the base of the natural logarithm, approximately 2.718282.71828.

STEP 4

Let's plug in what we know!
We want the bond to mature to $6500\$6500, so A=6500A = 6500.
The interest rate is 3.5%3.5\%, which as a decimal is 0.0350.035, so r=0.035r = 0.035.
The time is eight years, so t=8t = 8.

STEP 5

Now, we need to solve for PP, the initial amount.
Let's rearrange our formula to isolate PP:
P=AertP = \frac{A}{e^{r \cdot t}}

STEP 6

Substitute the values we have into this equation:
P=6500e0.0358P = \frac{6500}{e^{0.035 \cdot 8}}

STEP 7

Calculate the exponent first:
0.0358=0.280.035 \cdot 8 = 0.28

STEP 8

Now, calculate e0.28e^{0.28}:
e0.281.32313e^{0.28} \approx 1.32313

STEP 9

Finally, divide to find PP:
P=65001.323134913.97P = \frac{6500}{1.32313} \approx 4913.97

STEP 10

Susan should pay approximately $4913.97\$4913.97 for the bond now.

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