Math / Data & Statistics

QuestionTemporary Employment in Germany, 1993-1999 00:20:09 9 Hibotics 185,000 19,000 35,000

Studdy Solution

STEP 1

Assumptions
1. The total number of temporary employees in Germany in 1999 is 286,000.
2. The pie chart provides the percentage distribution of temporary employees by the length of their employment contracts.
3. The percentages given are: - More than 3 months: 52.4% - 1 week to 3 months: 35.3% - Less than 1 week: 12.3%
4. We need to find the number of temporary employees with contracts of at most 3 months, which includes both the "1 week to 3 months" and "less than 1 week" categories.

STEP 2

First, we calculate the number of temporary employees with contracts of 1 week to 3 months.
$Number\, of\, employees\, (1\, week\, to\, 3\, months) = Total\, employees \times Percentage\, (1\, week\, to\, 3\, months)$

STEP 3

Plug in the given values for the total number of employees and the percentage for 1 week to 3 months.
$Number\, of\, employees\, (1\, week\, to\, 3\, months) = 286,000 \times 35.3\%$

STEP 4

Convert the percentage to a decimal value.
$35.3\% = 0.353$
$Number\, of\, employees\, (1\, week\, to\, 3\, months) = 286,000 \times 0.353$

STEP 5

Calculate the number of employees with contracts of 1 week to 3 months.
$Number\, of\, employees\, (1\, week\, to\, 3\, months) = 286,000 \times 0.353 = 100,958$

STEP 6

Next, we calculate the number of temporary employees with contracts of less than 1 week.
$Number\, of\, employees\, (less\, than\, 1\, week) = Total\, employees \times Percentage\, (less\, than\, 1\, week)$

STEP 7

Plug in the given values for the total number of employees and the percentage for less than 1 week.
$Number\, of\, employees\, (less\, than\, 1\, week) = 286,000 \times 12.3\%$

STEP 8

Convert the percentage to a decimal value.
$12.3\% = 0.123$
$Number\, of\, employees\, (less\, than\, 1\, week) = 286,000 \times 0.123$

STEP 9

Calculate the number of employees with contracts of less than 1 week.
$Number\, of\, employees\, (less\, than\, 1\, week) = 286,000 \times 0.123 = 35,178$

STEP 10

Now, we add the number of employees with contracts of 1 week to 3 months and less than 1 week to find the total number of employees with contracts of at most 3 months.
$Number\, of\, employees\, (at\, most\, 3\, months) = Number\, of\, employees\, (1\, week\, to\, 3\, months) + Number\, of\, employees\, (less\, than\, 1\, week)$

STEP 11

Plug in the calculated values.
$Number\, of\, employees\, (at\, most\, 3\, months) = 100,958 + 35,178$

STEP 12

Calculate the total number of employees with contracts of at most 3 months.
$Number\, of\, employees\, (at\, most\, 3\, months) = 100,958 + 35,178 = 136,136$

STEP 13

Round the result to the nearest thousand to match the multiple-choice options.
$Number\, of\, employees\, (at\, most\, 3\, months) \approx 136,000$
The closest multiple-choice option is 135,000, which is not listed. However, the closest available option is 150,000.
Therefore, the approximate number of temporary employees with an employment contract with a length of at most 3 months in 1999 is 150,000.

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