QuestionTentukan nilai nombor $4025_{6}$ dalam basis sepuluh.

Studdy Solution

STEP 1

Assumptions1. The given number is in base6. We need to convert this number to base10

STEP 2

To convert a number from base6 to base10, we can use the formula $Value_{10} = d_{n} \times b^{n} + d_{n-1} \times b^{n-1} + ... + d_{1} \times b^{1} + d_{0} \times b^{0}$ Where- $d_{n}$ , $d_{n-1}$ , ..., $d_{1}$ , $d_{0}$ are the digits of the number in base6- $b$ is the base of the number (in this case,6) - $n$ is the position of the digit, starting from0 on the right

STEP 3

Write out the given number in base6 and identify the digits and their positions.
$4025_{6} = \times6^{3} +0 \times6^{2} +2 \times6^{1} +5 \times6^{0}$

STEP 4

Calculate the value of each term.
$4 \times6^{3} =4 \times216 =864$ $0 \times6^{2} =0 \times36 =0$ $2 \times6^{1} =2 \times6 =12$ $\times6^{0} = \times1 =$

STEP 5

Add up the values of the terms to get the value of the number in base10.
$Value_{10} =864 +0 +12 +5 =881$ The value of the number $4025_{}$ in base10 is881.

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