Math

QuestionSolve the inequality 3z1>z+9|3z - 1| > z + 9 and graph the solution set.

Studdy Solution

STEP 1

Assumptions1. The absolute value of a number is its distance from zero on the number line, regardless of direction. Therefore, it is always non-negative. . The inequality 3z1>z+9|3z-1|>z+9 is a complex inequality, where zz is a complex number.
3. We are asked to graph the solution set, which means we need to find all values of zz that satisfy the inequality and represent them on a complex plane.

STEP 2

The absolute value of a complex number z=a+biz=a+bi is defined as a2+b2\sqrt{a^2+b^2}. Therefore, we can rewrite the inequality as follows(z1)2>z+9\sqrt{(z-1)^2} > z+9

STEP 3

Square both sides of the inequality to remove the square root. This gives us(3z1)2>(z+9)2(3z-1)^2 > (z+9)^2

STEP 4

Expand both sides of the inequality9z26z+1>z2+18z+819z^2 -6z +1 > z^2 +18z +81

STEP 5

Rearrange the inequality to bring all terms to one side8z224z80>08z^2 -24z -80 >0

STEP 6

This is a quadratic inequality. To solve it, we first find the roots of the corresponding quadratic equation 8z224z80=08z^2 -24z -80 =0.

STEP 7

The roots of a quadratic equation ax2+bx+c=0ax^2 + bx + c =0 are given by the formula z=b±b24ac2az = \frac{-b \pm \sqrt{b^2 -4ac}}{2a}.

STEP 8

Substitute a=8a =8, b=24b = -24, and c=80c = -80 into the formula to find the rootsz=(24)±(24)248(80)28z = \frac{-(-24) \pm \sqrt{(-24)^2 -4*8*(-80)}}{2*8}

STEP 9

Calculate the rootsz=24±576+25616z = \frac{24 \pm \sqrt{576 +256}}{16}z=24±313616z = \frac{24 \pm \sqrt{3136}}{16}z=24±5616z = \frac{24 \pm56}{16}So, the roots are z=5z =5 and z=2z = -2.

STEP 10

The solution to the quadratic inequality 8z224z80>08z^2 -24z -80 >0 is the set of all zz that are not between the roots. Therefore, the solution set is z<2z < -2 or z>5z >5.

STEP 11

To graph the solution set, we draw a number line and mark the roots - and 55. We then shade the regions that represent the solution set, which are z<z < - and z>5z >5.

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