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Math

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PROBLEM

Solve the equation x+8=2x+1|x+8|=|2x+1|.

STEP 1

Assumptions1. The absolute value function is defined as a=a|a| = a for a0a \geq0 and a=a|a| = -a for a<0a <0.
. The equation x+8=x+1|x+8|=|x+1| has to be solved for xx.

STEP 2

The equation x+8=2x+1|x+8|=|2x+1| can be split into two cases based on the definition of absolute value functionCase1 x+8=2x+1x+8 =2x+1 when x+80x+8 \geq0 and 2x+102x+1 \geq0
Case2 x+8=(2x+1)x+8 = -(2x+1) when x+8<0x+8 <0 and 2x+1<02x+1 <0

STEP 3

olve the equation for Case1 x+8=2x+1x+8 =2x+1
Subtract xx from both sides to get8=x+18 = x +1

STEP 4

Subtract1 from both sides to solve for xxx=81=7x =8 -1 =7

STEP 5

Check if x=7x =7 satisfies the conditions for Case1 x+80x+8 \geq0 and 2x+102x+1 \geq0
Substitute x=7x =7 into these inequalities7+807+8 \geq0 and 2(7)+102(7)+1 \geq0
Both inequalities are true, so x=7x =7 is a valid solution for the equation.

STEP 6

olve the equation for Case2 x+8=(2x+1)x+8 = -(2x+1)This simplifies tox+8=2x1x +8 = -2x -1

STEP 7

Add 2x2x to both sides to get3x+=13x + = -1

STEP 8

Subtract8 from both sides to solve for xx3x=18=3x = -1 -8 = -

STEP 9

Divide both sides by3 to solve for xxx=9/3=3x = -9 /3 = -3

STEP 10

Check if x=3x = -3 satisfies the conditions for Case2 x+8<0x+8 <0 and 2x+<02x+ <0
Substitute x=3x = -3 into these inequalities3+8<0-3+8 <0 and 2(3)+<02(-3)+ <0
Both inequalities are false, so x=3x = -3 is not a valid solution for the equation.

SOLUTION

The solutions to the equation x+8=x+|x+8|=|x+| are x=7x =7.

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