Math

Question Find the cosine of -67.5 degrees.

Studdy Solution

STEP 1

1. The cosine function is an even function, which means cos(θ)=cos(θ)\cos(-\theta) = \cos(\theta).
2. The angle 67.5-67.5^{\circ} can be expressed as a sum or difference of angles whose cosine values are known.
3. The cosine of 4545^{\circ} and 22.522.5^{\circ} can be computed using half-angle formulas or known values.

STEP 2

1. Use the property of the cosine function being even to simplify the expression.
2. Express 67.5-67.5^{\circ} as a sum or difference of angles.
3. Use the cosine sum/difference formulas to compute the value.
4. Simplify the expression to find the final value.

STEP 3

Use the even property of the cosine function to simplify the expression.
cos(67.5)=cos(67.5) \cos(-67.5^{\circ}) = \cos(67.5^{\circ})

STEP 4

Express 67.567.5^{\circ} as a sum or difference of angles whose cosine values are known.
67.5=45+22.5 67.5^{\circ} = 45^{\circ} + 22.5^{\circ}

STEP 5

Use the cosine sum formula to compute the value:
cos(67.5)=cos(45+22.5) \cos(67.5^{\circ}) = \cos(45^{\circ} + 22.5^{\circ}) cos(67.5)=cos(45)cos(22.5)sin(45)sin(22.5) \cos(67.5^{\circ}) = \cos(45^{\circ})\cos(22.5^{\circ}) - \sin(45^{\circ})\sin(22.5^{\circ})

STEP 6

Compute the cosine and sine of 4545^{\circ}, which are known values.
cos(45)=22 \cos(45^{\circ}) = \frac{\sqrt{2}}{2} sin(45)=22 \sin(45^{\circ}) = \frac{\sqrt{2}}{2}

STEP 7

Use the half-angle formula to compute the cosine of 22.522.5^{\circ}.
cos(22.5)=1+cos(45)2 \cos(22.5^{\circ}) = \sqrt{\frac{1 + \cos(45^{\circ})}{2}} cos(22.5)=1+222 \cos(22.5^{\circ}) = \sqrt{\frac{1 + \frac{\sqrt{2}}{2}}{2}}

STEP 8

Simplify the expression for cos(22.5)\cos(22.5^{\circ}).
cos(22.5)=2+24 \cos(22.5^{\circ}) = \sqrt{\frac{2 + \sqrt{2}}{4}} cos(22.5)=2+22 \cos(22.5^{\circ}) = \frac{\sqrt{2 + \sqrt{2}}}{2}

STEP 9

Use the half-angle formula to compute the sine of 22.522.5^{\circ}.
sin(22.5)=1cos(45)2 \sin(22.5^{\circ}) = \sqrt{\frac{1 - \cos(45^{\circ})}{2}} sin(22.5)=1222 \sin(22.5^{\circ}) = \sqrt{\frac{1 - \frac{\sqrt{2}}{2}}{2}}

STEP 10

Simplify the expression for sin(22.5)\sin(22.5^{\circ}).
sin(22.5)=224 \sin(22.5^{\circ}) = \sqrt{\frac{2 - \sqrt{2}}{4}} sin(22.5)=222 \sin(22.5^{\circ}) = \frac{\sqrt{2 - \sqrt{2}}}{2}

STEP 11

Substitute the values of cos(45)\cos(45^{\circ}), cos(22.5)\cos(22.5^{\circ}), sin(45)\sin(45^{\circ}), and sin(22.5)\sin(22.5^{\circ}) into the sum formula.
cos(67.5)=(22)(2+22)(22)(222) \cos(67.5^{\circ}) = \left(\frac{\sqrt{2}}{2}\right)\left(\frac{\sqrt{2 + \sqrt{2}}}{2}\right) - \left(\frac{\sqrt{2}}{2}\right)\left(\frac{\sqrt{2 - \sqrt{2}}}{2}\right)

STEP 12

Simplify the expression to find the final value of cos(67.5)\cos(67.5^{\circ}).
cos(67.5)=12(2+222) \cos(67.5^{\circ}) = \frac{1}{2}(\sqrt{2 + \sqrt{2}} - \sqrt{2 - \sqrt{2}})

STEP 13

Conclude that the final value of cos(67.5)\cos(-67.5^{\circ}) is the same as cos(67.5)\cos(67.5^{\circ}).
cos(67.5)=12(2+222) \cos(-67.5^{\circ}) = \frac{1}{2}(\sqrt{2 + \sqrt{2}} - \sqrt{2 - \sqrt{2}})

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