Math

QuestionCalculate (9n28)3\left(\frac{9 n^{2}}{8}\right)^{3} and choose from: A) 9n68\frac{9 n^{6}}{8}, B) 729n68\frac{729 n^{6}}{8}, C) 729n6512\frac{729 n^{6}}{512}, D) 729n5512\frac{729 n^{5}}{512}.

Studdy Solution

STEP 1

Assumptions1. We are given the expression (9n8)3\left(\frac{9 n^{}}{8}\right)^{3} and we need to simplify it. . We are given four options and we need to select the correct one.

STEP 2

We need to apply the power of a power rule in exponents. The power of a power rule states that (am)n=am×n(a^m)^n = a^{m \times n}.(9n28)=(9×(n2))/8\left(\frac{9 n^{2}}{8}\right)^{} = \left(9^{} \times (n^{2})^{}\right) /8^{}

STEP 3

Calculate the value of 939^{3}, (n2)3(n^{2})^{3} and 838^{3}.
93=7299^{3} =729(n2)3=n6(n^{2})^{3} = n^{6}83=5128^{3} =512

STEP 4

Substitute the values back into the equation.
(9n28)3=729n6512\left(\frac{9 n^{2}}{8}\right)^{3} = \frac{729 n^{6}}{512}So, the correct answer is 729n6512\frac{729 n^{6}}{512}.

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