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Math

Math Snap

PROBLEM

The data represents a sample of gas that has a constant volume and number of particles. Use the data to answer these two questions.
When the Kelvin temperature of the gas quadruples (increases by a factor of four), the volume of
\begin{tabular}{|c|c|c|} \hline Trial & \begin{tabular}{c} Temperature \\ (K)(\mathbf{K}) \end{tabular} & \begin{tabular}{c}
Volume \\
(mL)
\end{tabular} \\
\hline 1 & 200 & 400 \\
\hline 2 & 300 & 600 \\
\hline 3 & 400 & 800 \\
\hline 4 & 600 & 1200 \\
\hline 5 & 800 & 1600 \\
\hline
\end{tabular}
the gas becomes \qquad -
\square

STEP 1

What is this asking?
If we multiply the temperature of some gas by 4, what happens to its volume?
Watch out!
The table gives a lot of data, but we only need two rows to figure out the relationship between temperature and volume.
Don't get distracted!

STEP 2

1. Find the relationship
2. Calculate the new volume

STEP 3

Let's look at the table and see what's up.
When the temperature is 200200 K, the volume is 400400 mL.
When the temperature is 400400 K, the volume is 800800 mL.
Hmm, interesting!

STEP 4

It looks like when the temperature doubles from 200200 K to 400400 K, the volume doubles from 400400 mL to 800800 mL.
This suggests a direct relationship between temperature and volume!
In other words, if we multiply the temperature by some number, the volume gets multiplied by that same number!

STEP 5

The problem says the temperature quadruples, which means it gets multiplied by 4.
Since temperature and volume have a direct relationship, the volume will also get multiplied by 4!

STEP 6

Let's pick a starting temperature and volume from the table.
Let's use trial 1: 200200 K and 400400 mL.
If we multiply the temperature by 44, we get 2004=800200 \cdot 4 = 800 K.

STEP 7

Now, let's multiply the volume by 44: 4004=1600400 \cdot 4 = 1600 mL.
So, when the temperature quadruples to 800800 K, the volume quadruples to 16001600 mL.
Awesome!

SOLUTION

When the Kelvin temperature quadruples, the volume of the gas also quadruples.

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