Math  /  Data & Statistics

QuestionThe director of health services is concerned about a possible flu outbreak at her college. She surveyed 100 randomiy selected residents from the college's dormitories to see whether they had received a preventative flu shot. The results are shown below. What is the probability that a dormitory resident chosen at random from this group has had a flu shot, given that he is male?
Rosidonts At Collego Dormitorios \begin{tabular}{|c|c|c|c|} \hline & Male & Female & Total \\ \hline Had Flu Shot & 39 & 41 & 80 \\ \hline \begin{tabular}{c} Didn't Have \\ Flue Shot \end{tabular} & 12 & 8 & 20 \\ \hline Total & 51 & 49 & 100 \\ \hline \end{tabular} 51100\frac{51}{100} 1317\frac{13}{17} 39100\frac{39}{100} 3980\frac{39}{80}

Studdy Solution

STEP 1

1. We are given a table of data showing the number of male and female residents who had or did not have a flu shot.
2. We need to find the probability that a randomly chosen male resident has had a flu shot.

STEP 2

1. Identify the relevant data from the table.
2. Calculate the conditional probability.

STEP 3

Identify the number of male residents who had a flu shot and the total number of male residents.
From the table: - Number of males who had a flu shot: 39 - Total number of males: 51

STEP 4

Calculate the probability that a randomly chosen male resident has had a flu shot.
The probability P(Flu ShotMale) P(\text{Flu Shot} \mid \text{Male}) is given by:
P(Flu ShotMale)=Number of males who had a flu shotTotal number of malesP(\text{Flu Shot} \mid \text{Male}) = \frac{\text{Number of males who had a flu shot}}{\text{Total number of males}}
Substitute the values:
P(Flu ShotMale)=3951P(\text{Flu Shot} \mid \text{Male}) = \frac{39}{51}
Simplify the fraction:
P(Flu ShotMale)=1317P(\text{Flu Shot} \mid \text{Male}) = \frac{13}{17}
The probability that a dormitory resident chosen at random from this group has had a flu shot, given that he is male, is:
1317 \boxed{\frac{13}{17}}

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