Math

Question Find the value of xx in the equation ex=5e^{x}=5. The correct statements are: x=ln5x=\ln 5, x=log5ex=\log _{5} e, and to the nearest hundredth, x1.61x \approx 1.61.

Studdy Solution

STEP 1

1. The expression ex=5e^{x}=5 involves the natural exponential function, where ee is the base of the natural logarithm.
2. The natural logarithm function, denoted as ln\ln, is the inverse of the natural exponential function.
3. The logarithm function can be used to solve for xx in the equation ex=5e^{x}=5.
4. The logarithm base conversion formula can be used to convert between different bases of logarithms.

STEP 2

1. Solve the equation ex=5e^{x}=5 for xx.
2. Evaluate the natural logarithm of 55 to find the value of xx.
3. Determine if x=log5ex=\log _{5} e is true by using the base conversion formula for logarithms.
4. Calculate the value of xx to the nearest hundredth.
5. Assess the truth of the statement x=5ex=\frac{5}{e}.

STEP 3

Take the natural logarithm of both sides of the equation to solve for xx.
ln(ex)=ln(5) \ln(e^{x}) = \ln(5)

STEP 4

Use the property of logarithms that ln(ex)=x\ln(e^{x}) = x to simplify the left side of the equation.
x=ln(5) x = \ln(5)

STEP 5

Evaluate ln(5)\ln(5) to find the value of xx.
xln(5) x \approx \ln(5)

STEP 6

Use a calculator or other computational tool to find the numerical value of ln(5)\ln(5) to the nearest hundredth.
x1.61 x \approx 1.61

STEP 7

Use the base conversion formula for logarithms to determine if x=log5ex=\log _{5} e is true.
log5e=ln(e)ln(5) \log _{5} e = \frac{\ln(e)}{\ln(5)}

STEP 8

Simplify the right side of the equation, knowing that ln(e)=1\ln(e) = 1.
log5e=1ln(5) \log _{5} e = \frac{1}{\ln(5)}

STEP 9

Evaluate the right side of the equation using the previously found value of ln(5)\ln(5).
log5e11.61 \log _{5} e \approx \frac{1}{1.61}

STEP 10

Calculate the numerical value to the nearest hundredth.
log5e0.62 \log _{5} e \approx 0.62

STEP 11

Compare the calculated value of xx to the given approximations to determine which are correct.
x1.61 x \approx 1.61

STEP 12

Assess the truth of the statement x=5ex=\frac{5}{e} by comparing it to the previously found value of xx.
x5e x \neq \frac{5}{e}
Based on the steps above, the following statements about the value of xx are true: - x=ln5x=\ln 5 - To the nearest hundredth, x1.61x \approx 1.61
The other statements are false: - To the nearest hundredth, x0.70x \approx 0.70 is false because x1.61x \approx 1.61. - x=log5ex=\log _{5} e is false because log5e0.62\log _{5} e \approx 0.62. - To the nearest hundredth, x1.84x \approx 1.84 is false because x1.61x \approx 1.61. - x=5ex=\frac{5}{e} is false because xx is the exponent to which ee must be raised to get 5, not a fraction.

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