Math

QuestionLet the son's age be xx. Then, father's age is 2x2x. Twenty-five years ago, 2x25=27(x25)2x - 25 = 27(x - 25). Find xx.

Studdy Solution

STEP 1

Assumptions1. Let's denote the present age of the son as (in years). . Let's denote the present age of the father as F (in years).
3. According to the problem, the father is twice as old as his son, so we can write this as F =.
4. Twenty five years ago, the father was twenty seven times as old as his son, so we can write this as F -25 =27(S -25).

STEP 2

We start by setting up the first equation from the problem statement.
=2 =2

STEP 3

Next, we set up the second equation from the problem statement.
25=27(S25) -25 =27(S -25)

STEP 4

Now we have a system of two equations. We can solve this system by substitution or elimination. In this case, substitution seems to be the easier method. We substitute F from the first equation into the second equation.
225=27(S25)2 -25 =27(S -25)

STEP 5

Next, we simplify the equation by distributing the27 on the right side.
225=276752 -25 =27 -675

STEP 6

We then move the terms involving to one side of the equation and the constants to the other side.
272=675+2527 -2 =675 +25

STEP 7

implify the equation to find the value of.
25=70025 =700

STEP 8

Finally, we solve for by dividing both sides of the equation by25.
=700/25 =700 /25

STEP 9

Calculate the value of.
=700/25=28 =700 /25 =28The present age of the son is28 years.

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