Math  /  Geometry

QuestionThe figure shows a 350 foot tower on the side of a hill that forms a 55^{\circ} angle with the horizontal. Find the length of each of the two guy wires that are anchored 110 feet uphill and downhill from the tower's base and extend to the top of the tower.
Part (a) What is the length of the uphill guy wire? 357.6 feet (Round to the nearest tenth as needed.)
Part (b) What is the length of the downhill guy wire? \square feet (Round to the nearest tenth as needed.)

Studdy Solution

STEP 1

What is this asking? We need to find the lengths of two wires supporting a tower on a hill, one anchored uphill and the other downhill. Watch out! Don't forget to account for the hill's angle when calculating the wire lengths.
It's not just a straight up-and-down triangle!

STEP 2

1. Visualize and label
2. Uphill wire length
3. Downhill wire length

STEP 3

Imagine the tower, hill, and uphill wire forming a triangle.
Label the tower height as 350350 feet.
The horizontal distance from the tower base to the uphill anchor is 110110 feet.
The angle between the hill and the horizontal is 55^\circ.

STEP 4

We can find the distance along the hill to the anchor point using trigonometry.
Since tan(5)=vertical distancehorizontal distance\tan(5^\circ) = \frac{\text{vertical distance}}{\text{horizontal distance}}, the vertical distance is 110tan(5)9.60110 \cdot \tan(5^\circ) \approx 9.60 feet.
This means the hill length to the uphill anchor is 1102+9.602110.35\sqrt{110^2 + 9.60^2} \approx 110.35 feet using the Pythagorean theorem.

STEP 5

Now imagine the downhill scenario.
The tower height remains 350350 feet, the horizontal distance is still 110110 feet, but the hill slopes down.
The vertical distance is the same as calculated before, 9.609.60 feet, but this time it's downwards.
The hill length to the downhill anchor is also the same, approximately 110.35110.35 feet.

STEP 6

The top of the tower is 350350 feet vertically above its base, and the uphill anchor is 9.609.60 feet vertically below the base.
So, the vertical distance between the top of the tower and the uphill anchor is 350+9.60=359.60350 + 9.60 = 359.60 feet.

STEP 7

Now we have a right triangle with legs of 110110 feet (horizontal distance) and 359.60359.60 feet (vertical distance).
The uphill wire length is the hypotenuse.
Using the Pythagorean theorem, the uphill wire length is 1102+359.602376.0\sqrt{110^2 + 359.60^2} \approx 376.0 feet.

STEP 8

The top of the tower is 350350 feet vertically above its base, and the downhill anchor is 9.609.60 feet vertically below the base.
So, the vertical distance between the top of the tower and the downhill anchor is 3509.60=340.40350 - 9.60 = 340.40 feet.

STEP 9

We have another right triangle with legs of 110110 feet (horizontal distance) and 340.40340.40 feet (vertical distance).
The downhill wire is the hypotenuse.
Using the Pythagorean theorem, the downhill wire length is 1102+340.402357.6\sqrt{110^2 + 340.40^2} \approx 357.6 feet.

STEP 10

**(a)** The uphill guy wire is approximately **376.0** feet long. **(b)** The downhill guy wire is approximately **357.6** feet long.

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