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Math

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PROBLEM

The following table represents an exponential function.
\begin{tabular}{|c|c|} \hlinexx & yy \\ \hline 0 & 4 \\ \hline 1 & 2 \\ \hline 2 & 1 \\ \hline 3 & 12\frac{1}{2} \\ \hline 4 & 14\frac{1}{4} \\ \hline \end{tabular}
The exponential function represented by the table can be written in the form y=abxy=a b^{x}. Find the values for aa and bb.
a=a=\square b=b= \square

STEP 1

1. The function is exponential and can be expressed as y=abx y = a b^x .
2. The table provides specific values of x x and corresponding y y .

STEP 2

1. Use the initial value to determine a a .
2. Use the ratio of consecutive y y -values to determine b b .
3. Verify the values of a a and b b using additional points.

STEP 3

The value of y y when x=0 x = 0 is 4. Since y=ab0=a y = a b^0 = a , we have:
a=4 a = 4

STEP 4

To find b b , use the ratio of consecutive y y -values. For example, when x=1 x = 1 , y=2 y = 2 and when x=0 x = 0 , y=4 y = 4 . Therefore:
b=y1y0=24=12 b = \frac{y_1}{y_0} = \frac{2}{4} = \frac{1}{2}

SOLUTION

Verify the values of a a and b b using additional points. Check x=2 x = 2 , where y=1 y = 1 :
y=ab2=4(12)2=4×14=1 y = a b^2 = 4 \left(\frac{1}{2}\right)^2 = 4 \times \frac{1}{4} = 1 The values are consistent with the table, confirming a=4 a = 4 and b=12 b = \frac{1}{2} .
The exponential function is:
a=4 a = 4 b=12 b = \frac{1}{2}

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