QuestionCalculate the moles of rubidium chloride ( $\mathrm{RbCl}$ ) produced from $303 \, \mathrm{g}$ , using significant digits.

Studdy Solution

STEP 1

Assumptions1. The chemical formula for rubidium chloride is $\mathrm{RbCl}$ . The amount of rubidium chloride produced is $303g$
3. The molar mass of rubidium chloride is the sum of the molar mass of rubidium (Rb) and chlorine (Cl)
4. The molar mass of rubidium (Rb) is $85.47g/mol$
5. The molar mass of chlorine (Cl) is $35.45g/mol$
6. The number of moles is calculated by dividing the mass of the substance by its molar mass

STEP 2

First, we need to find the molar mass of rubidium chloride. We can do this by adding the molar mass of rubidium and chlorine.
$Molar\, mass\, of\, RbCl = Molar\, mass\, of\, Rb + Molar\, mass\, of\, Cl$

STEP 3

Now, plug in the given values for the molar mass of rubidium and chlorine to calculate the molar mass of rubidium chloride.
$Molar\, mass\, of\, RbCl =85.47g/mol +35.45g/mol$

STEP 4

Calculate the molar mass of rubidium chloride.
$Molar\, mass\, of\, RbCl =85.47g/mol +35.45g/mol =120.92g/mol$

STEP 5

Now that we have the molar mass of rubidium chloride, we can find the number of moles produced. This is done by dividing the mass of rubidium chloride by its molar mass.
$Number\, of\, moles = Mass\, of\, RbCl / Molar\, mass\, of\, RbCl$

STEP 6

Plug in the values for the mass of rubidium chloride and the molar mass of rubidium chloride to calculate the number of moles.
$Number\, of\, moles =303g /120.92g/mol$

STEP 7

Calculate the number of moles of rubidium chloride produced.
$Number\, of\, moles =303g /120.92g/mol =2.506\, moles$ The number of moles of rubidium chloride produced is2.506 moles.

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