Math

Question Simplify the expression x3x+9+8x2+3x\frac{x}{3 x+9}+\frac{8}{x^{2}+3 x}.

Studdy Solution

STEP 1

Assumptions
1. We are given the expression x3x+9+8x2+3x\frac{x}{3x+9}+\frac{8}{x^2+3x}.
2. We need to simplify the expression by combining the terms.
3. We assume that x0x \neq 0 and x3x \neq -3 to avoid division by zero in the denominators.

STEP 2

First, we need to find a common denominator for the two fractions in order to combine them. The common denominator should be a multiple of both denominators 3x+93x+9 and x2+3xx^2+3x.

STEP 3

Factor out the common term in the denominators.
3x+9=3(x+3)3x+9 = 3(x+3) x2+3x=x(x+3)x^2+3x = x(x+3)

STEP 4

Now we can see that the common denominator is 3x(x+3)3x(x+3) because it includes both factors 33 and x(x+3)x(x+3).

STEP 5

Rewrite each fraction with the common denominator.
x3x+9=x3(x+3)=x3x(x+3)3x3x\frac{x}{3x+9} = \frac{x}{3(x+3)} = \frac{x}{3x(x+3)} \cdot \frac{3x}{3x}

STEP 6

Similarly, rewrite the second fraction with the common denominator.
8x2+3x=8x(x+3)=83x(x+3)33\frac{8}{x^2+3x} = \frac{8}{x(x+3)} = \frac{8}{3x(x+3)} \cdot \frac{3}{3}

STEP 7

Now, multiply the numerators by the appropriate factors to get the common denominator.
x3x+9=3x23x(x+3)\frac{x}{3x+9} = \frac{3x^2}{3x(x+3)} 8x2+3x=243x(x+3)\frac{8}{x^2+3x} = \frac{24}{3x(x+3)}

STEP 8

Combine the two fractions with the common denominator.
x3x+9+8x2+3x=3x23x(x+3)+243x(x+3)\frac{x}{3x+9}+\frac{8}{x^2+3x} = \frac{3x^2}{3x(x+3)} + \frac{24}{3x(x+3)}

STEP 9

Add the numerators of the fractions.
3x23x(x+3)+243x(x+3)=3x2+243x(x+3)\frac{3x^2}{3x(x+3)} + \frac{24}{3x(x+3)} = \frac{3x^2 + 24}{3x(x+3)}

STEP 10

Look for common factors in the numerator that can be factored out.

STEP 11

Since there are no common factors to factor out in the numerator 3x2+243x^2 + 24, we can leave the numerator as it is.

STEP 12

Thus, the simplified expression is:
3x2+243x(x+3)\frac{3x^2 + 24}{3x(x+3)}
This is the simplified form of the given expression.

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