PROBLEM
The functions g and t are defined for x∈R as follows:
g:x→4x−5t:x→x2−5x+1 (a) Find t(6)
(b) Show that t(g(x))=16x2−60x+51
STEP 1
1. We are given two functions: g(x)=4x−5 and t(x)=x2−5x+1.
2. We need to evaluate t(6).
3. We need to show that t(g(x))=16x2−60x+51.
STEP 2
1. Evaluate t(6).
2. Substitute g(x) into t(x) to find t(g(x)).
3. Simplify the expression for t(g(x)).
4. Verify that the simplified expression matches 16x2−60x+51.
STEP 3
Substitute x=6 into t(x):
t(6)=62−5(6)+1
STEP 4
Simplify the expression:
t(6)=36−30+1 t(6)=7
STEP 5
Substitute g(x)=4x−5 into t(x):
t(g(x))=((4x−5)2)−5(4x−5)+1
STEP 6
Expand (4x−5)2:
(4x−5)2=(4x)2−2(4x)(5)+52 =16x2−40x+25
STEP 7
Substitute the expanded form back into the expression for t(g(x)):
t(g(x))=(16x2−40x+25)−5(4x−5)+1
STEP 8
Simplify the expression:
t(g(x))=16x2−40x+25−(20x−25)+1
STEP 9
Combine like terms:
t(g(x))=16x2−40x+25−20x+25+1 t(g(x))=16x2−60x+51
SOLUTION
Verify that the expression matches 16x2−60x+51.
The expression matches, confirming the result.
The value of t(6) is 7, and it is shown that t(g(x))=16x2−60x+51.
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