Math

QuestionA garden has a perimeter of 48 meters. Its length is twice the width. Find the length and width of the garden.

Studdy Solution

STEP 1

Assumptions1. The garden is rectangular in shape. . The length of the garden is twice its width.
3. The perimeter of the garden is48 meters.

STEP 2

The formula for the perimeter of a rectangle is given byPerimeter=2×(Length+Width)Perimeter =2 \times (Length + Width)

STEP 3

We know that the length of the garden is twice its width. Let's denote the width as 'w'. Then the length would be '2w'.

STEP 4

Substitute the values of length and width in terms of 'w' into the perimeter formula.
48=2×(2w+w)48 =2 \times (2w + w)

STEP 5

implify the equation.
48=2×3w48 =2 \times3w

STEP 6

olve for 'w' by dividing both sides of the equation by6.
w=48/6w =48 /6

STEP 7

Calculate the value of 'w'.
w=48/6=w =48 /6 =So, the width of the garden is meters.

STEP 8

Now, we can find the length of the garden by multiplying the width by2.
Length=2×WidthLength =2 \times Width

STEP 9

Substitute the value of the width into the equation to find the length.
Length=2×8Length =2 \times8

STEP 10

Calculate the length of the garden.
Length=2×8=16Length =2 \times8 =16So, the length of the garden is16 meters.
The dimensions of the garden are16 meters by8 meters.

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