Math  /  Algebra

QuestionThe graph below shows a transformation of y=2xy=2^{x}.
Write an equation of the form y=a2x+ky=a \cdot 2^{x}+k for the graph above. yy - \square Enter an algebraic expression [more..]

Studdy Solution

STEP 1

1. The base function is y=2x y = 2^x .
2. The transformation involves vertical shifts and possibly vertical stretching or compression.
3. The horizontal asymptote at y=4 y = -4 suggests a vertical shift.

STEP 2

1. Determine the vertical shift k k .
2. Determine the vertical stretch/compression factor a a .
3. Write the transformed equation.

STEP 3

Identify the vertical shift k k from the horizontal asymptote. Since the horizontal asymptote is at y=4 y = -4 , the function has been shifted down by 4 units. Thus, k=4 k = -4 .

STEP 4

To determine the vertical stretch/compression factor a a , observe the graph and identify a point on the transformed curve. If a specific point is given or can be identified, use it to solve for a a .
Assume the point (0,3) (0, -3) is on the transformed graph. Substitute this point into the equation y=a2x+k y = a \cdot 2^x + k :
3=a204 -3 = a \cdot 2^0 - 4
Since 20=1 2^0 = 1 , we have:
3=a14 -3 = a \cdot 1 - 4 3=a4 -3 = a - 4
Solve for a a :
a=3+4 a = -3 + 4 a=1 a = 1

STEP 5

Write the equation of the transformed graph using the values of a a and k k determined:
y=12x4 y = 1 \cdot 2^x - 4
Simplify the equation:
y=2x4 y = 2^x - 4
The equation of the transformed graph is:
y=2x4 y = 2^x - 4

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