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Math

Math Snap

PROBLEM

Find the length of one leg of a 45459045^{\circ}-45^{\circ}-90^{\circ} triangle with hypotenuse 22222 \sqrt{2} units.

STEP 1

Assumptions1. The triangle is a 45459045^{\circ}-45^{\circ}-90^{\circ} triangle, also known as an isosceles right triangle.
. The hypotenuse of the triangle measures 2222 \sqrt{} units.
3. In a 45459045^{\circ}-45^{\circ}-90^{\circ} triangle, the length of the hypotenuse is \sqrt{} times the length of each leg (since the legs are of equal length).

STEP 2

We can express the length of the hypotenuse in terms of the length of one leg (let's call it aa) using the property of a 45459045^{\circ}-45^{\circ}-90^{\circ} triangle.
Hypotenuse=a2Hypotenuse = a \sqrt{2}

STEP 3

Now, we can plug in the given value for the hypotenuse to solve for aa.
222=a222 \sqrt{2} = a \sqrt{2}

STEP 4

To solve for aa, we can divide both sides of the equation by 2\sqrt{2}.
a=2222a = \frac{22 \sqrt{2}}{\sqrt{2}}

SOLUTION

implify the equation to find the length of one leg of the triangle.
a=2222=22a = \frac{22 \sqrt{2}}{\sqrt{2}} =22So, the length of one leg of the triangle is22 units.

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