Math  /  Algebra

Question2x+5y=132x + 5y = 13

Studdy Solution

STEP 1

What is this asking? We're looking for numbers xx and yy that make the equation 2x+5y=132x + 5y = 13 true! Watch out! There are lots of possible answers here, not just one.
Don't get stuck thinking there's only one perfect pair of xx and yy!

STEP 2

1. Explore the equation
2. Find a solution
3. Find another solution!

STEP 3

Let's **rewrite** the equation to make it easier to work with.
We'll get yy by itself!
We start with 2x+5y=132x + 5y = 13. **Subtract** 2x2x from both sides to get 5y=132x5y = 13 - 2x.
Now, **divide** both sides by 55 to isolate yy.
This gives us y=132x5y = \frac{13 - 2x}{5}.
Awesome!

STEP 4

Now, let's **pick a value** for xx and see what yy we get!
Let's start simple with x=0x = 0.
Plugging that into our equation gives us y=13205=135y = \frac{13 - 2 \cdot 0}{5} = \frac{13}{5}.
So one solution is x=0x = 0 and y=135y = \frac{13}{5}!

STEP 5

Let's **try another value** for xx just for fun!
How about x=1x = 1?
Substituting x=1x = 1 into our equation gives us y=13215=115y = \frac{13 - 2 \cdot 1}{5} = \frac{11}{5}.
So another solution is x=1x = 1 and y=115y = \frac{11}{5}!
See? Lots of answers!

STEP 6

We found two solutions!
One is x=0x = 0 and y=135y = \frac{13}{5}.
Another is x=1x = 1 and y=115y = \frac{11}{5}.
There are infinitely many more, but these two are great examples!

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