QuestionIdentify the element $X$ with 10 electrons and a charge of -1.

Studdy Solution

STEP 1

Assumptions1. The ion $X^-$ has10 electrons. . The ion has a negative1 charge.
3. The atomic number of an element is equal to the number of protons in its nucleus.
4. A neutral atom has an equal number of protons and electrons.
5. The charge of an ion is determined by the difference between the number of protons and electrons.

STEP 2

First, we need to understand that the negative charge of the ion indicates that it has one more electron than it has protons.

STEP 3

Since the ion has10 electrons and a negative1 charge, it must have one less proton. This means the ion has9 protons.
$Number\, of\, protons = Number\, of\, electrons - Charge$

STEP 4

Plug in the values for the number of electrons and the charge to calculate the number of protons.
$Number\, of\, protons =10 - (-1)$

STEP 5

Calculate the number of protons.
$Number\, of\, protons =10 - (-1) =9$

STEP 6

Now that we have the number of protons, we can identify the element. The atomic number of an element is equal to the number of protons in its nucleus. Therefore, the element with atomic number9 is Fluorine.
The ion $X^-$ is a Fluorine ion.

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QuestionIdentify the element $X$ with 10 electrons and a charge of -1.

Studdy Solution

STEP 1

STEP 2

First, we need to understand that the negative charge of the ion indicates that it has one more electron than it has protons.

STEP 3

Since the ion has10 electrons and a negative1 charge, it must have one less proton. This means the ion has9 protons.
$Number\, of\, protons = Number\, of\, electrons - Charge$

STEP 4

Plug in the values for the number of electrons and the charge to calculate the number of protons.
$Number\, of\, protons =10 - (-1)$

STEP 5

Calculate the number of protons.
$Number\, of\, protons =10 - (-1) =9$

STEP 6

Now that we have the number of protons, we can identify the element. The atomic number of an element is equal to the number of protons in its nucleus. Therefore, the element with atomic number9 is Fluorine.
The ion $X^-$ is a Fluorine ion.

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QuestionIdentify the element XXX with 10 electrons and a charge of -1.

Studdy Solution

STEP 1

STEP 2

First, we need to understand that the negative charge of the ion indicates that it has one more electron than it has protons.

STEP 3

Since the ion has10 electrons and a negative1 charge, it must have one less proton. This means the ion has9 protons.Number of protons=Number of electrons−ChargeNumber\, of\, protons = Number\, of\, electrons - ChargeNumberofprotons=Numberofelectrons−Charge

STEP 4

Plug in the values for the number of electrons and the charge to calculate the number of protons.Number of protons=10−(−1)Number\, of\, protons =10 - (-1)Numberofprotons=10−(−1)

STEP 5

Calculate the number of protons.Number of protons=10−(−1)=9Number\, of\, protons =10 - (-1) =9Numberofprotons=10−(−1)=9

STEP 6

Now that we have the number of protons, we can identify the element. The atomic number of an element is equal to the number of protons in its nucleus. Therefore, the element with atomic number9 is Fluorine.The ion X−X^-X− is a Fluorine ion.

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QuestionIdentify the element $X$ with 10 electrons and a charge of -1.

Since the ion has10 electrons and a negative1 charge, it must have one less proton. This means the ion has9 protons.
$Number\, of\, protons = Number\, of\, electrons - Charge$

Plug in the values for the number of electrons and the charge to calculate the number of protons.
$Number\, of\, protons =10 - (-1)$

Calculate the number of protons.
$Number\, of\, protons =10 - (-1) =9$

Now that we have the number of protons, we can identify the element. The atomic number of an element is equal to the number of protons in its nucleus. Therefore, the element with atomic number9 is Fluorine.
The ion $X^-$ is a Fluorine ion.