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QuestionIdentify the element X\mathrm{X} if the ion X2−\mathrm{X}^{2-} has 18 electrons and a -2 charge.

Studdy Solution

STEP 1

Assumptions1. The ion X−\mathrm{X}^{-} has18 electrons. . The ion has a negative charge.

STEP 2

We know that in a neutral atom, the number of electrons equals the number of protons.

STEP 3

Since the ion X2−\mathrm{X}^{2-} has a negative2 charge, this means it has2 more electrons than it has protons.

STEP 4

So, to find the number of protons, we subtract2 from the total number of electrons.
Protons=Electrons−ChargeProtons = Electrons - Charge

STEP 5

Plug in the values for the number of electrons and the charge to calculate the number of protons.
Protons=18−(−2)Protons =18 - (-2)

STEP 6

Calculate the number of protons.
Protons=18−(−2)=20Protons =18 - (-2) =20

STEP 7

Now that we know the number of protons, we can identify the element. The atomic number of an element is equal to the number of protons in its nucleus.

STEP 8

Look up the element with atomic number20 in the periodic table.The element with atomic number20 is Calcium (Ca).
So, X\mathrm{X} is Calcium (Ca).

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