Solve a problem of your own!
Download the Studdy App!

Math

Math Snap

PROBLEM

Solve the equation log2xlog27=log2(x1)\log _{2} x - \log _{2} 7 = \log _{2}(x - 1).

STEP 1

Assumptions1. The base of all logarithms in the equation is.
. The variable x is the same in all parts of the equation.
3. The logarithmic equation is valid for x >0 and x ≠1.

STEP 2

We can use the properties of logarithms to simplify the equation. The property logbalogbc=logbac\log_b a - \log_b c = \log_b \frac{a}{c} allows us to combine the left side of the equation.
log2xlog27=log2(x1)\log{2} x-\log{2}7=\log{2}(x-1)becomeslog2x7=log2(x1)\log{2} \frac{x}{7} = \log{2}(x-1)

STEP 3

Since the base of the logarithms on both sides of the equation is the same (base2), we can set the arguments of the logarithms equal to each other.
x7=x1\frac{x}{7} = x -1

STEP 4

To solve for x, we first get rid of the fraction by multiplying every term by7.
x=7x7x =7x -7

STEP 5

Next, we rearrange the equation to isolate x. Subtract x from both sides to get0=x70 =x -7

STEP 6

Add to both sides to isolate the term with x=6x =6x

SOLUTION

Finally, divide both sides by6 to solve for xx=76x = \frac{7}{6}So, the solution to the logarithmic equation log2xlog27=log2(x1)\log{2} x-\log{2}7=\log{2}(x-1) is x=76x = \frac{7}{6}.

Was this helpful?
banner

Start understanding anything

Get started now for free.

OverviewParentsContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord