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Math

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PROBLEM

Find the earthquake magnitude using R=log(I1)R=\log \left(\frac{I}{1}\right) for I=4×104I=4 \times 10^{4}. Round to the nearest hundredth.

STEP 1

Assumptions1. The formula for the magnitude of an earthquake is given by R=log(0)R=\log \left(\frac{}{_{0}}\right). The intensity of a zero-level earthquake, 0_{0}, is13. The intensity of the earthquake in question, $$, is $4 \times10^{4}$ times the intensity of a zero-level earthquake

STEP 2

First, we need to find the intensity of the earthquake in question. We can do this by multiplying the intensity of a zero-level earthquake by the given factor.
=I0×Factor = I_{0} \times Factor

STEP 3

Now, plug in the given values for the intensity of a zero-level earthquake and the factor to calculate the intensity of the earthquake.
=1××10 =1 \times \times10^{}

STEP 4

Calculate the intensity of the earthquake.
=1×4×104=4×104 =1 \times4 \times10^{4} =4 \times10^{4}

STEP 5

Now that we have the intensity of the earthquake, we can find the magnitude of the earthquake using the given formula.
R=log(0)R=\log \left(\frac{}{_{0}}\right)

STEP 6

Plug in the values for the intensity of the earthquake and the intensity of a zero-level earthquake into the formula.
R=log(4×1041)R=\log \left(\frac{4 \times10^{4}}{1}\right)

STEP 7

implify the fraction inside the logarithm.
R=log(4×104)R=\log \left(4 \times10^{4}\right)

SOLUTION

Calculate the magnitude of the earthquake.
R=log(4×104)4.60R=\log \left(4 \times10^{4}\right) \approx4.60The magnitude of an earthquake that is 4×1044 \times10^{4} times as intense as a zero-level earthquake is approximately4.60.

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