Math  /  Algebra

QuestionThe number of cells in a tumor doubles every 3.5 months. If the tumor begins with a single cell, how many cells will there be after 3 years? after 4 years?
How may cells will there be after 3 years? \square (Do not round until the final answer. Then round to the nearest whole number as needed.)

Studdy Solution

STEP 1

What is this asking? If a tumor starts with one cell and doubles in size every 3.5 months, how many cells will there be after 3 years and 4 years? Watch out! Don't forget to convert years to months and be careful with how many times the cells double!

STEP 2

1. Convert years to months
2. Calculate the number of doublings
3. Calculate the number of cells

STEP 3

There are 12 months in a year, so 3 years is 312=363 \cdot 12 = \textbf{36} **months**!

STEP 4

Similarly, 4 years is 412=484 \cdot 12 = \textbf{48} **months**!

STEP 5

The cells double every 3.5 months, and we have 36 months total.
So, in 3 years, the cells double 36/3.510.2936 / 3.5 \approx \textbf{10.29} **times**.

STEP 6

For 4 years (48 months), the cells double 48/3.513.7148 / 3.5 \approx \textbf{13.71} **times**.

STEP 7

We start with 1 cell.
After the first doubling, we have 12=21 \cdot 2 = 2 cells.
After the second doubling, we have 22=42 \cdot 2 = 4 cells, and so on.
This is just like 22 raised to the power of the number of doublings!
So, after approximately 10.29 doublings, we have 210.291155.852^{10.29} \approx \textbf{1155.85} cells.

STEP 8

Similarly, after approximately 13.71 doublings, we'll have 213.7111193.862^{13.71} \approx \textbf{11193.86} cells.

STEP 9

After 3 years, there will be approximately **1156** cells (rounded to the nearest whole number).
After 4 years, there will be approximately **11194** cells (rounded to the nearest whole number).

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