Math

QuestionThe plumber charges a flat rate of \$50 plus \$28 per hour. If the bill was \$134, how long did he work?

Studdy Solution

STEP 1

Assumptions1. The plumber charges a flat rate of 50..Theplumbercharges50. . The plumber charges 28 per hour for his work.
3. The final bill was $134.
4. The final bill includes both the flat rate and the hourly charges.

STEP 2

First, we need to calculate the amount that was charged for the hourly work. We can do this by subtracting the flat rate from the final bill.
Hourlycharges=FinalbillFlatrateHourly\, charges = Final\, bill - Flat\, rate

STEP 3

Now, plug in the given values for the final bill and the flat rate to calculate the hourly charges.
Hourlycharges=$134$50Hourly\, charges = \$134 - \$50

STEP 4

Calculate the hourly charges.
Hourlycharges=$134$50=$84Hourly\, charges = \$134 - \$50 = \$84

STEP 5

Now that we have the hourly charges, we can find out how long the plumber was at the house. This can be done by dividing the hourly charges by the hourly rate.
Time=Hourlycharges/HourlyrateTime = Hourly\, charges / Hourly\, rate

STEP 6

Plug in the values for the hourly charges and the hourly rate to calculate the time.
Time=$84/$28Time = \$84 / \$28

STEP 7

Calculate the time the plumber spent at the house.
Time=$84/$28=3hoursTime = \$84 / \$28 =3\, hoursThe plumber was at the house for3 hours.

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