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Math

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PROBLEM

The population of Austin was 494,000 and grows by 3%3\% yearly. Find yy after 10 years using y=494(1.03)ty=494(1.03)^{t}.

STEP 1

Assumptions1. The initial population of Austin, Texas, is494,000.
. The population increases by3% each year.
3. The growth is exponential, meaning the population increases by a fixed percentage each year.
4. We are looking for the population10 years after the beginning of the decade.

STEP 2

The general form of an exponential growth model is y=a(1+r)ty = a(1 + r)^t, where- yy is the final amount- aa is the initial amount- rr is the growth rate (expressed as a decimal)
- tt is the time (in years)

STEP 3

In this case, the initial amount aa is the initial population, which is494,000. The growth rate rr is3%, or0.03 when expressed as a decimal. We can substitute these values into the exponential growth model.
y=494(1+0.03)ty =494(1 +0.03)^t

STEP 4

implify the equation.
y=494(1.03)ty =494(1.03)^tThis is the exponential growth model that represents the population of Austin, Texas.

STEP 5

To find the population10 years after the beginning of the decade, we substitute t=10t =10 into the equation.
y=494(1.03)10y =494(1.03)^{10}

SOLUTION

Calculate the value of yy.
y=494(1.03)10664y =494(1.03)^{10} \approx664This means that the population of Austin, Texas,10 years after the beginning of the decade is approximately664,000.

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