Math

Question Find the probability that a state will be hit by a major tornado (F4\mathrm{F} 4 or F5) two years in a row, given the probability of a major tornado in any single year is 19\frac{1}{9}. Round the answer to five decimal places.

Studdy Solution

STEP 1

Assumptions1. The probability of the state being hit by a major tornado in any single year is 19\frac{1}{9}. . The events of the state being hit by a major tornado in each year are independent.
3. We want to find the probability that the state will be hit by a major tornado two years in a row.

STEP 2

For independent events, the probability of both events occurring is the product of their individual probabilities. So, we can calculate the probability of the state being hit by a major tornado two years in a row by multiplying the probability of it being hit in one year by itself.
(hit two years in a row)=(hit in one year)×(hit in one year)(\text{hit two years in a row}) =(\text{hit in one year}) \times(\text{hit in one year})

STEP 3

Now, plug in the given probability for the state being hit in one year to calculate the probability of it being hit two years in a row.
(hit two years in a row)=19×19(\text{hit two years in a row}) = \frac{1}{9} \times \frac{1}{9}

STEP 4

Calculate the probability of the state being hit by a major tornado two years in a row.
(hit two years in a row)=19×19=181(\text{hit two years in a row}) = \frac{1}{9} \times \frac{1}{9} = \frac{1}{81}

STEP 5

Finally, we need to round the probability to five decimal places as needed. The decimal representation of 181\frac{1}{81} is approximately 0.0123456790.012345679, which rounded to five decimal places is 0.012350.01235.
(hit two years in a row)=0.01235(\text{hit two years in a row}) =0.01235The probability that the state will be hit by a major tornado two years in a row is 0.012350.01235.

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